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Bunuel
The ratio of the degree measures of the angles of a triangle is 2:3:4. Which of the following is the sum of the degree measures of the smallest and largest angles?

A) 40°

B) 80°

C) 100°

D) 120°

E) 140°

Given ratio of angles of a triangle is 2:3:4, 2x + 3x + 4x = 180

9x = 180
x = 20

smallest = 2x = 2*20 = 40
largest = 4x = 4*20 = 80

40 + 80 = 120 ans D
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Given ration 2:3:4 so angles can be considered 2x,3x,4x
2x+3x+4x=180
x=20

Smallest angle 40 and Largest Angle 80. Sum of Smallest and Largest angle is 120
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Bunuel
The ratio of the degree measures of the angles of a triangle is 2:3:4. Which of the following is the sum of the degree measures of the smallest and largest angles?

A) 40°

B) 80°

C) 100°

D) 120°

E) 140°


As per the ratio, the smallest angle is 2x and largest angle is 4x. So the sum of this 2 angles is 6x. We can deduce that sum is basically multiple of 6.
Option D works.

Thus , option D is the answer.
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Hi All,

We're told that the ratio of the degree measures of the angles of a triangle is 2:3:4. We're asked which of the following is the sum of the degree measures of the SMALLEST and LARGEST angles.

Since the ratio of the angles is 2:3:4, we can refer to those 3 angles as 2X, 3X and 4X, respectively. A triangle has 180 total degrees and those 3 angles would sum to 9X, meaning that 9X = 180.

9X = 180
X = 20

The 3 angles would be 40, 60 and 80. The sum of the smallest and largest angles would be 40+80 = 120.

Final Answer:

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Bunuel
The ratio of the degree measures of the angles of a triangle is 2:3:4. Which of the following is the sum of the degree measures of the smallest and largest angles?

A) 40°

B) 80°

C) 100°

D) 120°

E) 140°

We can create the equation:

2x + 3x + 4x = 180

9x = 180

x = 20

The smallest angle is 2x = 40, and the largest angle is 4x = 80. Thus, their sum is 40 + 80 = 120.

Answer: D
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2x + 3x + 4x = 180
9x = 180
x = \(\frac{180}{9}\)
x= 20

2x = 2 x 20 =40
3x = 3 x 20 = 60
4x = 4 x 20 = 80

Sum of the degree measure of the smallest & the largest angle = 40 + 80 =120

IMO D
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Bunuel
The ratio of the degree measures of the angles of a triangle is 2 : 3 : 4. Which of the following is the sum of the degree measures of the smallest and largest angles?

A. 40°
B. 80°
C. 100°
D. 120°
E. 140°

smallest angle: \(180°*\frac{2}{9}\)
largest angle: \(180°*\frac{4}{9}\)

Sum of smallest and largest angle:
\(180°(\frac{2}{9}+\frac{4}{9})=180°(\frac{2}{3})=60°*2=120°\)

Answer (D)
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Solution


Given:
    • The ratio of the degree measures of the angles of a triangle is 2: 3: 4.

To find:
    • The sum of the degree measures of the smallest and largest angles.

Approach and Working:
If we assume the angles as 2k, 3k and 4k, then
    • Sum of smallest and largest angles = 2k + 4k = 6k, which is a multiple of 6.
    • Among the given choices, only one option is a multiple of 6 (which is 120°)

Hence, the correct answer is option D.

Answer: D

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Ratio= 2:3:4. So I can say that the angles are 2x,3x and 4x where x is variable. Also, sum of angles of a triangle is 180. So 2x+3x+4x = 9x = 180. So x = 20. This the angles are 2x = 40, 3x = 60, 4x = 80. So answer = 120 = D.

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2+3+4=9.
180÷9*2+4=120

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