Last visit was: 21 Apr 2026, 22:16 It is currently 21 Apr 2026, 22:16
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,739
Own Kudos:
810,496
 [2]
Given Kudos: 105,815
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,739
Kudos: 810,496
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
avatar
thule123
Joined: 24 Apr 2019
Last visit: 09 Jun 2020
Posts: 1
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,739
Own Kudos:
Given Kudos: 105,815
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,739
Kudos: 810,496
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
jfranciscocuencag
Joined: 12 Sep 2017
Last visit: 17 Aug 2024
Posts: 227
Own Kudos:
144
 [1]
Given Kudos: 132
Posts: 227
Kudos: 144
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
thule123

X<140

35 = 7*5

\(\frac{5*7*x}{5^2*2^2}\) = INTEGER

x must be at least 20 (5*2^2) to be div by 100.

So

20 * 3 = 60 ... less than 140... Prime numbers = 2,3,5.

20 * 7 = 140 ... cant be cuz x must be less than 140.

Hence C
User avatar
Arro44
Joined: 04 Jun 2018
Last visit: 14 Aug 2022
Posts: 658
Own Kudos:
752
 [1]
Given Kudos: 362
Location: United States
Concentration: General Management, Finance
GMAT 1: 730 Q47 V44
GPA: 3.4
Products:
GMAT 1: 730 Q47 V44
Posts: 658
Kudos: 752
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I am a little confused by this question, are we looking for the maximum number of possible prime factors for x?
User avatar
jfranciscocuencag
Joined: 12 Sep 2017
Last visit: 17 Aug 2024
Posts: 227
Own Kudos:
Given Kudos: 132
Posts: 227
Kudos: 144
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Arro44
I am a little confused by this question, are we looking for the maximum number of possible prime factors for x?

Yes, Arro44

Considering than x must be at least 20.
User avatar
Arro44
Joined: 04 Jun 2018
Last visit: 14 Aug 2022
Posts: 658
Own Kudos:
Given Kudos: 362
Location: United States
Concentration: General Management, Finance
GMAT 1: 730 Q47 V44
GPA: 3.4
Products:
GMAT 1: 730 Q47 V44
Posts: 658
Kudos: 752
Kudos
Add Kudos
Bookmarks
Bookmark this Post
jfranciscocuencag
Arro44
I am a little confused by this question, are we looking for the maximum number of possible prime factors for x?

Yes, Arro44

Considering than x must be at least 20.

Thank you, then I understand your solution and also agree that it is the correct one.

I was a little confused by the worked which led me to check the number of prime factors for 20...

Best regards,
Chris
User avatar
CareerGeek
Joined: 20 Jul 2017
Last visit: 21 Apr 2026
Posts: 1,286
Own Kudos:
Given Kudos: 162
Location: India
Concentration: Entrepreneurship, Marketing
GMAT 1: 690 Q51 V30
WE:Education (Education)
GMAT 1: 690 Q51 V30
Posts: 1,286
Kudos: 4,430
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If x is a positive integer less than 140 and 35x/100 is also an integer, then how many different positive prime factors could x have?

A. 1
B. 2
C. 3
D. 4
E. 5

x<140.
35x/100 = 7x/20 is an integer
—> x should be a multiple of 20 less than 140.

So, possible values of x are
20 = 2^2*5 (2 possible prime factors)
40 = 2^3*5 (2 possible prime factors)
60 = 2^2*3*5 (3 possible prime factors)
80 = 2^4*5 (2 possible prime factors)
100 = 2^2*5^2 (2 possible prime factors)
120 = 2^3*3*5 (3 possible prime factors)

So, x can have either 2 or 3 possible prime factors.

IMO Option should be B or C.

Or question should have asked maximum possible prime factors for answer to be C.

Bunuel The question looks ambiguous. Pls help

Posted from my mobile device
User avatar
Arro44
Joined: 04 Jun 2018
Last visit: 14 Aug 2022
Posts: 658
Own Kudos:
Given Kudos: 362
Location: United States
Concentration: General Management, Finance
GMAT 1: 730 Q47 V44
GPA: 3.4
Products:
GMAT 1: 730 Q47 V44
Posts: 658
Kudos: 752
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Dillesh4096
Bunuel
If x is a positive integer less than 140 and 35x/100 is also an integer, then how many different positive prime factors could x have?

A. 1
B. 2
C. 3
D. 4
E. 5

x<140.
35x/100 = 7x/20 is an integer
—> x should be a multiple of 20 less than 140.

So, possible values of x are
20 = 2^2*5 (2 possible prime factors)
40 = 2^3*5 (2 possible prime factors)
60 = 2^2*3*5 (3 possible prime factors)
80 = 2^4*5 (2 possible prime factors)
100 = 2^2*5^2 (2 possible prime factors)
120 = 2^3*3*5 (3 possible prime factors)

So, x can have either 2 or 3 possible prime factors.

IMO Option should be B or C.

Or question should have asked maximum possible prime factors for answer to be C.

Bunuel The question looks ambiguous. Pls help

Posted from my mobile device

After re-reading the question twice I now feel like the part "how many different prime factors could x have" implies that we are looking for the maximum number.
However, I had the same problem initially.
User avatar
CareerGeek
Joined: 20 Jul 2017
Last visit: 21 Apr 2026
Posts: 1,286
Own Kudos:
Given Kudos: 162
Location: India
Concentration: Entrepreneurship, Marketing
GMAT 1: 690 Q51 V30
WE:Education (Education)
GMAT 1: 690 Q51 V30
Posts: 1,286
Kudos: 4,430
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Arro44
Dillesh4096
Bunuel
If x is a positive integer less than 140 and 35x/100 is also an integer, then how many different positive prime factors could x have?

A. 1
B. 2
C. 3
D. 4
E. 5

x<140.
35x/100 = 7x/20 is an integer
—> x should be a multiple of 20 less than 140.

So, possible values of x are
20 = 2^2*5 (2 possible prime factors)
40 = 2^3*5 (2 possible prime factors)
60 = 2^2*3*5 (3 possible prime factors)
80 = 2^4*5 (2 possible prime factors)
100 = 2^2*5^2 (2 possible prime factors)
120 = 2^3*3*5 (3 possible prime factors)

So, x can have either 2 or 3 possible prime factors.

IMO Option should be B or C.

Or question should have asked maximum possible prime factors for answer to be C.

Bunuel The question looks ambiguous. Pls help

Posted from my mobile device

After re-reading the question twice I now feel like the part "how many different prime factors could x have" implies that we are looking for the maximum number.
However, I had the same problem initially.

I believe any question in GMAT should convey one exact meaning irrespective whosoever is reading. As we can clearly see x can have either 2 or 3 values, I’m not convinced with the assumption.

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Math Expert
109739 posts