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IMO C

LCM (2,3,5) = 30

x will be multiple of 30 i.e. 30k
and 3x = 90k

Number divisible by 2, 3, 5, and 3x = LCM (2,3,5,90k) = 90k

Smallest three digit number = 180.
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Bunuel
A positive integer x is divisible by 2,3, and 5. What is the smallest three-digit number that is divisible by 2, 3, 5, and 3x?

A. 120
B. 150
C. 180
D. 210
e. 300

If x is divisible by 2, 3 and 5, it is divisible by the LCM of 2, 3 and 5. So x is divisible by 30. Thus, 3x is divisible by 90. So we want the "smallest three digit number that is divisible by 2, 3, 5 and some unknown multiple of 90". There is no way to answer that question without knowing what that unknown multiple of 90 is, i.e. without knowing what 3x is. If 3x is 900, the answer is 900, and if 3x is 90, the answer is 180, among many other possibilities.

There's something wrong with the question.
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A positive integer x is divisible by 2,3, and 5. What is the smallest three-digit number that is divisible by 2, 3, 5, and 3x?

A. 120
B. 150
C. 180 --> correct: x is divisible by 2,3, and 5 i.e. x is multiple of 2,3, & 5 i.e. x = LCM(2,3, & 5) = 2*3*5*d =30d, where d = 0(1)n, n is a +ve integer. So the smallest three-digit number that is divisible by 2, 3, 5, and 3x = LCM (2,3,5, & 3x) = LCM (2,3,5, & 3*30d) = 3*30d=90d, so the smallest three-digit number that is divisible by 2, 3, 5, and 3x = 90, 180, or 270, ....
D. 210
e. 300

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