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yrozenblum
If \(x^2 + \frac{1}{x^2} = 4\), what is the value of \(x^4 + \frac{1}{x^4}\)?

A. 2
B. 4
C. 6
D. 14
E. 16

Remember you can solve the question just by squaring both side and subtract -2

Will correspond to 14

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yrozenblum
If \(x^2 + \frac{1}{x^2} = 4\), what is the value of \(x^4 + \frac{1}{x^4}\)?

A. 2
B. 4
C. 6
D. 14
E. 16

\(x^2 + \frac{1}{x^2} = 4\)

Squaring both sides we get

\((x^2)^2 + (\frac{1}{x^2})^2 + 2*x^2*\frac{1}{x^2} = (4)^2\)

\(x^4 + \frac{1}{x^4} + 2 = 16\)

\(x^4 + \frac{1}{x^4} = 16 - 2 = 14\)

Option D
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­Classic (x + y)^2 recognition:

­
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