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08 Oct 2008, 06:42
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The total cost of water for one year in Community Z of 120,000 homes is $75,000. If the cost were to increase to $80,000 for the community, by approximately what percent would the average cost of water for each household in Community Z?
A) 70%
B) 13%
C) 7%
D) 5%
E) 1.3%
A) 70%
B) 13%
C) 7%
D) 5%
E) 1.3%
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08 Oct 2008, 06:58
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I think the question here is the percentage increase in cost per household.
the answer is C
cost per household before increase=75,000/120,000=.625
cost per household after increase=80,000/120,000=.666
the difference= .666-.625=.041
the percentage increase =.041/.625*100=6.56%
the answer is approx. 7%
the answer is C
cost per household before increase=75,000/120,000=.625
cost per household after increase=80,000/120,000=.666
the difference= .666-.625=.041
the percentage increase =.041/.625*100=6.56%
the answer is approx. 7%
08 Oct 2008, 08:24
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I would say the same:
% increase: (80,000-75,000)/75,000 aprox. 7%
Am I missing something?
Cheers
% increase: (80,000-75,000)/75,000 aprox. 7%
Am I missing something?
Cheers
