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gddunton
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GMAT Prep Rate 16 Dec 2009, 12:32
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Has trouble figuring out where to start with this one.

Any help would be appreciated.

Thanks,



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GMAT Prep Rate 16 Dec 2009, 12:49
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I'm having trouble reading the text in this .jpg. Could you type the question and answer choices?
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gddunton
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GMAT Prep Rate 16 Dec 2009, 13:12
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During a trip on an expressway, Don drove a total of X miles. His average speed on a certain 5 mile stretch was 30 miles an hour and the average speed for the remainder of the trip was 60 miles an hour.

His travel time was what percent greater than it would have been if he had traveled at a constant rate of 60MPH hos whole trip.

1) 8.5%
2) 50%
3) (x/12)%
4) (60/x)%
5) (500/x)%
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gddunton
During a trip on an expressway, Don drove a total of X miles. His average speed on a certain 5 mile stretch was 30 miles an hour and the average speed for the remainder of the trip was 60 miles an hour.

His travel time was what percent greater than it would have been if he had traveled at a constant rate of 60MPH hos whole trip.

1) 8.5%
2) 50%
3) (x/12)%
4) (60/x)%
5) (500/x)%
Show more

Initially, 5miles at 30mph
(x-5) miles at 60mph

total time = 5/30 + (x-5)/60 = (x+5)/60
expected time = x/60

more time taken = (x+5 -x)/60 = 1/12

%time more taken = (1/12)/(x)/60 * 100 = 500/x %
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kp1811
gddunton
During a trip on an expressway, Don drove a total of X miles. His average speed on a certain 5 mile stretch was 30 miles an hour and the average speed for the remainder of the trip was 60 miles an hour.

His travel time was what percent greater than it would have been if he had traveled at a constant rate of 60MPH hos whole trip.

1) 8.5%
2) 50%
3) (x/12)%
4) (60/x)%
5) (500/x)%

Initially, 5miles at 30mph
(x-5) miles at 60mph

total time = 5/30 + (x-5)/60 = (x+5)/60
expected time = x/60

more time taken = (x+5 -x)/60 = 1/12

%time more taken = (1/12)/(x)/60 * 100 = 500/x %
Show more

agreed with above solution



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