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19 Aug 2015, 01:35
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (02:03) correct
30%
(02:06)
wrong
based on 225
sessions
History
Date
Time
Result
Not Attempted Yet
7 points are marked on a straight line and another 8 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
A. 21
B. 91
C. 168
D. 196
E. 364
A. 21
B. 91
C. 168
D. 196
E. 364
19 Aug 2015, 01:48
Kudos
Bookmarks
Bunuel
select 2 points from one line and one from another.
7C2 * 8C1 [ 2 points from the line containing 7 points and 1 from the line containing 8 points]
+
8C2 * 7C1 [ 2 points from the line containing 8 points and 1 from the line containing 7 points]
=364 [E]
General Discussion
19 Aug 2015, 02:16
Kudos
Bookmarks
Bunuel
To construct a triangle you require three points.
So, choose one point from one line and choose two points from the other line.
let us say 7 points line is A and 8 points line B
you can select one point from A in 7c1 ways and two points from B in 8c2 ways=7c1*8c2 ('and' means multiplication)
similarly, you can select one point from B in 8c1 ways and two points from A in 7c2 ways=8c1*7c2
7*28+8*21=364
Hence, the correct option is E
