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15 May 2010, 11:50
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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67% (00:53) correct
33%
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The average of 4 different positive integers is 125. If the largest of these integers is 150, what is the least possible value of the smallest integer?
* 1
* 2
* 12
* 53
* 100
* 1
* 2
* 12
* 53
* 100
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17 May 2010, 02:45
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nverma
D,
Let the numbers be a,b,c and d
then \(\frac{a+b+c+d}{4}\) \(= 125\)
a+ b+c +d = 500
d = 150
a+b+c= 350
now 150 is the largest among the lot, then let c= 149 and b = 148 then equation becomes
a+ 148+ 149 = 350 or a = 53
