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02 Oct 2007, 13:34
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (01:15) correct
9%
(01:42)
wrong
based on 817
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There are 15 slate rocks, 20 pumice rocks, and 10 granite rocks randomly distributed in a certain field. If 2 rocks are to be chosen at random and without replacement, what is the probability that both rocks will be slate rocks?
A) 1/3
B) 7/22
C) 1/9
D) 7/66
E) 2/45
A) 1/3
B) 7/22
C) 1/9
D) 7/66
E) 2/45
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02 Oct 2007, 13:57
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Total No of Rocks = 45
Probability of choosing 1st Slate Rock = 15/45
Probability of choosing 2nd Slate Rock = 14/44 (Without replacement)
So combined probability = 15/45*14/44 = 7/66
So, D.
- Brajesh
Probability of choosing 1st Slate Rock = 15/45
Probability of choosing 2nd Slate Rock = 14/44 (Without replacement)
So combined probability = 15/45*14/44 = 7/66
So, D.
- Brajesh
04 Oct 2007, 00:39
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avenger
15/45 * 14/44 ---> 7/66.
Just add up the total rocks. Then u calculate first prob, then u must subtract the one slate rock from both numerator and denominator.
Ans D.
