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04 Feb 2021, 23:30
Kudos
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Train X: 30
Train Y: 35
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
63% (02:51) correct
37%
(03:01)
wrong
based on 1056
sessions
History
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Train X travels from City A to City B, a distance of 630 miles, in t hours.
Train Y completes the same trip in (t – 3) hours.
Select possible average speeds for train X and train Y, respectively, in miles per hour (mph). The answers must be jointly consistent with the problem. Make only one selection in each column.
Train Y completes the same trip in (t – 3) hours.
Select possible average speeds for train X and train Y, respectively, in miles per hour (mph). The answers must be jointly consistent with the problem. Make only one selection in each column.
| Train X | Train Y | Speed in mph |
| 15 | ||
| 18 | ||
| 21 | ||
| 30 | ||
| 35 | ||
| 45 |
ShowHide Answer
Official Answer
Train X: 30
Train Y: 35
05 Feb 2021, 00:43
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Sajjad1994
Train X a takes three more hour, so divide 630 by all the options given and where ever the difference is 3, the higher speed is of Y and lesser is that of X.
\(\frac{630}{15}=\frac{2*3*3*5*7}{3*5}=42\)
\(\frac{630}{18}=\frac{2*3*3*5*7}{2*3*3}=35\)
\(\frac{630}{21}=\frac{2*3*3*5*7}{3*7}=30\)
\(\frac{630}{30}=\frac{2*3*3*5*7}{2*3*5}=21\)
\(\frac{630}{35}=\frac{2*3*3*5*7}{5*7}=18\)
21-18=3, so speed of X is 30, while that of Y is 35.
| Train X | Train Y | Speed in mph |
| 15 | ||
| 18 | ||
| 21 | ||
| X | 30 | |
| Y | 35 | |
| 45 |
General Discussion
29 Jun 2025, 06:28
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