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19 Sep 2024, 07:51
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Diameter: 0.5 inches, Thickness: 0.3 inches: $4,000
Diameter: 0.8 inches, Thickness: 0.2 inches: $9,600
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
61% (03:11) correct
39%
(03:18)
wrong
based on 875
sessions
History
Date
Time
Result
Not Attempted Yet
Pharmwin, a premium pharmaceutical company, has decided to gift a labeled gold coin as memento to each of its 2,000 employees on its 50th anniversary. Moldwell, a metal molding factory, has been approached for casting these mementos. Moldwell suggests that Pharmwin must provide equivalent quantity of gold in the form of bars, which Moldwell shall then mold to cast the 2,000 coins. Moldwell suggests that it will charge a flat $12 per coin that measures 1.0 inches in diameter and 0.1 inches in thickness. Moldwell further suggests that for any other dimensions of the coin, the price of casting shall vary directly with the diameter of the coin and inversely with the thickness of the coin. Pharmwin is considering two dimensions for the coins - diameter of 0.5 inches and thickness of 0.3 inches or diameter of 0.8 inches and thickness of 0.2 inches.
From the table, select the values that, approximately, indicate the total cost of casting 2,000 coins for the dimensions being considered by Pharmwin. Make only two selections, one in each column.
From the table, select the values that, approximately, indicate the total cost of casting 2,000 coins for the dimensions being considered by Pharmwin. Make only two selections, one in each column.
| Diameter: 0.5 inches, Thickness: 0.3 inches | Diameter: 0.8 inches, Thickness: 0.2 inches | Total cost of casting |
| $4,000 | ||
| $4,800 | ||
| $9,600 | ||
| $19,200 | ||
| $40,000 |
ShowHide Answer
Official Answer
Diameter: 0.5 inches, Thickness: 0.3 inches: $4,000
Diameter: 0.8 inches, Thickness: 0.2 inches: $9,600
19 Sep 2024, 08:56
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Given that 1 coin of dimensions 1inch diameter and 0.1inch thickness costs $12.
Price ∝ diameter
price ∝ 1/thickness
-0.5inch diameter & 0.3inch thickness
Here the diameter is 1/2 of the original dimensions and thickness is 3 times the original.
So price per coin= (12 x 1/2)/3 = $2
Price for 2000 coins = 2 x 2000 = $4000
-0.8inch diameter & 0.2inch thick
Similarly, price per coin = (12 x 4/5)/2 = $4.8
Price for 2000 coins = 4.8 x 2000 = $9600
Price ∝ diameter
price ∝ 1/thickness
-0.5inch diameter & 0.3inch thickness
Here the diameter is 1/2 of the original dimensions and thickness is 3 times the original.
So price per coin= (12 x 1/2)/3 = $2
Price for 2000 coins = 2 x 2000 = $4000
-0.8inch diameter & 0.2inch thick
Similarly, price per coin = (12 x 4/5)/2 = $4.8
Price for 2000 coins = 4.8 x 2000 = $9600
05 Oct 2024, 06:12
Kudos
Bookmarks
We know that:
Price ∝ diameter and Price ∝ 1/thickness
Let diameter: d, thickness: t
Price, p = k(d/t), where k: some constant
A coin of 1inch diameter and 0.1inch thickness costs $12.
Let's put these values in the above equation:
12 = k(1/0.1) => k = 1.2
Now we can simply find the price for different given dimensions:
Diameter: 0.5 inches, Thickness: 0.3 inches:
d=0.5, t=0.3 and k=1.2
p = 1.2*(0.5/0.3) => p = 2
Price of a coin: $2
Price of 2000 coins = 2*2000 => $4,000
Diameter: 0.8 inches, Thickness: 0.2 inches:
d=0.8, t=0.2 and k=1.2
[color=#0f0f0f]p = 1.2*(0.8/0.2) => p = 4.8
Price of a coin: $4.8
Price of 2000 coins = 4.8*2000 => $9,600[/color]
Price ∝ diameter and Price ∝ 1/thickness
Let diameter: d, thickness: t
Price, p = k(d/t), where k: some constant
A coin of 1inch diameter and 0.1inch thickness costs $12.
Let's put these values in the above equation:
12 = k(1/0.1) => k = 1.2
Now we can simply find the price for different given dimensions:
Diameter: 0.5 inches, Thickness: 0.3 inches:
d=0.5, t=0.3 and k=1.2
p = 1.2*(0.5/0.3) => p = 2
Price of a coin: $2
Price of 2000 coins = 2*2000 => $4,000
Diameter: 0.8 inches, Thickness: 0.2 inches:
d=0.8, t=0.2 and k=1.2
[color=#0f0f0f]p = 1.2*(0.8/0.2) => p = 4.8
Price of a coin: $4.8
Price of 2000 coins = 4.8*2000 => $9,600[/color]
