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A museum issued a certain number of annual passes. 15% of the passes were never activated. Of the activated passes, 40% were Family passes and 60% were Individual passes. Among the activated passes, 21/34 of the Family passes and 1/3 of the Individual passes were used fewer than 6 times during the month.
Of all passes issued, A percent are Family passes that were used fewer than 6 times during the month, and B percent are Individual passes that were used fewer than 6 times during the month.
Select for
A and for
B the options that complete the statement so that it is most accurate based on the information provided. Make only two selections, one in each column.
Let’s us assume the number of annual passes to be 10200.
Easier method: 85% = 17/20
For family pass = 40%*(85%*Total) = (2/5)*(17/20)*T
Less than 6month = (21/34)*(2/5)*(17/20)*T = (21/100)*T
For Individual pass = 60%*(85% of total) = (3/5)*(17/20)*T
Less than 6 months = (1/3)*(3/5)*(17/20)*T = (17/100)*T
Fraction out of total = ?
Less than 6 month value is divided by T.
(21/100) =
21%(17/100) =
17% Traditional method:
15% of the annual passes are not activated.
85% of the annual passes are activated
= (85/100)* 10200
= 8670
Out of the 8670 activated passes.
Family passes = 40%*( 8670) = 3468
Individual passes = 60%(8670) = 8670-3468 = 5202.
Lesser than 6 month passes :
Family passes = (21/34)*3468 = 2142
Individual passes = (1/3)*5202 = 1734
Hence, percentage of less than 6 month passes out of the total.
2142/10200 =21%
1734/10200 = 17%
A =21% and B=17%