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C1 (Gold:Green:White) = 1:3:2 (Total = 6)
C2 = 4:1:3 (Total = 8)
We are given that the total of gold = total of green breads

For container we will evaluate multiples of 6 as breads can't be in decimal numbers.

In option 1 45 we get the equation as
9 + (4B/8) = 27 + (1B/8)
Thus, B = 48 which is not an option for C2

In option 2 72 we get the equation as
12 + (4B/8) = 36 + (1B/8)
B= 64

Therefore the answers are C1: 72, C2: 64
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Given Container 1 - Go:Gr:W = 1:3:2 let x be the multiplier here

Container 2 - Go:Gr:W = 4:1:3 let y be the multiplier here

Given total green balls is equal to total Gold balls
gold balls - 1x+4y
green balls - 3x+y
1x+4y = 3x+y
so x/y = 3/2

let X be 3a and Y be 2a

so total balls in container 1 - 3a+9a+6a = 18a
in C2 = 8a+2a+6a = 16a

C1:C2 = 9:8
which should also satisfy the condition equal to 6x:8y (as x = 3a, 18a = 6x, similarly y = 2a, 16a = 8y)

from options multiple of 9 are 45,54,72,81
from which to satisfy 6x, the answer should be even
54, 72 are the only two valid options

case 1 - 54/9 = 6 ---> 6*8 = 48 no option there in the question options
case 2 - 72/9 = 8 ----> 8*8 = 64 we do have an option, thus the answer

72, 64
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Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.



total beads in container 1 is 1x:3x:2x ; 6x and
total beads in container 2 is 4y:1y : 3y ; 8y

upon mixing both containers total gold and green are same

x+4y = 3x+y
3y = 2x
x= 3y/2

we can say that container 1 has to have 18n & container 2 16n
n is multiple value of n= 4
we get

container 1 has 72 and container 2 64


72 & 64 are correct options
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Gold Green White Total
1) x 3x 2x => 6x = 9y
2) 4y y 3y => 8y = 16x/3

Given that x+4y = 3x+y
Thus 3y = 2x.
Now 6x = 6( 3y/2) = 9y
& 8y = 8(2x/3) = 16x/3

Thus Total in Container 1 must be multiple of 6 & 9 both, Therefore a/q to options it will be 54.
Similarly Total in Container 2 must be multiple of 16 & 8 both, Therefore a/q to options it will be 64
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First take container 1
Let total number of beads in it be x
for denominator = 1+3+2=6
So gold = 1/6 of x
green = 3/6 =1/2 of x

Let total in container 2 be y
denominator = 4 + 1 + 3 =8
gold = 4/8 = 1/2 of y
green = 1/8 of y

We are given
Gold in both= green in both
so
x/6 +y/2 = x/2 +y/8
= x/6 - x/2 = y/8 - y/2
= 8x=9y
or x/y= 9/8
We need something from options in this proportion
So
Container 1 = 72
container 2= 64
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Answer: Container 1 = 72, Container 2 = 64
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Container 1: g:G:W=1:3:2
Total in C1 =1x+3x+2x=6x
Container 2: g:G:W=4:1:3
Total in C2 = 4y+1y+3y= 8y
Total gold beads in C1+C2 = Total Green beads in C1+C2
1x+4y = 3x+1y
3y = 2x
x/y =3/2

Total in C1/Total in C2 = 6(3)/8(2)=9/8
The answers must be in ratio 9:8. (Try multiplying both ratios by 2,3....8,9 until we get to choices)

Container 1= 72
Container 2= 64
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Container 1 total bead=a; gold:green:white=1:3:2=> gold=a, green=3a, white=2a
Container 2 total beads=b; gold:green:white=4:1:3=> gold=4b, green=b, white=3b

The total gold beads was equal to total green beads
a+4b=3a+b=> 3b=2a
Looking at the options a=81 and b=54 makes the pair
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So ratio of Gold: Green: White beads in both the containers are
C1= x : 3x : 2x = 6x
C2= 4y : y : 3y = 8y

We are given that across the containers combined, total number of gold beads are equal to total number of green beads
x + 4y = 3x = y
after simplifying we get x = 1.5 y

So C1 = 6x = 6 * 1.5y = 9y
C2 = 8y

So in container C2, bead's number should be multiple of 8, so we get C2 = 40 in this case C1 = 45; When C2 = 64, C1 = 72; and when C2 = 72, C1 = 81. However, we know than C1 = 6x = ( 45, 72, and 81) only 72 is multiple of 6, and rest all are not.

So as per my calculation C1 = 72, and C2 = 64
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Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.
In Container 1, let gold beads, green beads & white beads be x, 3x & 2x respectively

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.
In Container 2, let gold beads, green beads & white beads be 4y, y & 3y respectively.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

The total number of gold beads = x + 4y = The total number of green beads = 3x + y
x + 4y = 3x + y
3y = 2x
y = 2x/3

The total number of beads in Container 1 = x + 3x + 2x = 6x
The total number of beads in Container 2 = 4y + y + 3y = 8y

The total number of beads in Container 1/ The total number of beads in Container 2 = 6x/8y = 3/4 * x/y = 3/4 * 3/2 = 9/8 = 18/16 = 36/32 = 54/48 = 72/64

Container 1Container 2
7264
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x+4y=3x+y
3y=2x

x:y=3:2

cont 1: cont 2
6(3):8(2)
18:16
9:8
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I will use abbreviations for, Gold - 'go' , Green - 'gr', White - 'wh'

Container 1(C1),
gp:gr:wh :: 1:3:2
Could say total '6a' beads in C1

Container 2,
go:gr:wh :: 4:1:3
Could say total '8b' beads in C2

total 'go' in both C1 and C2 = total 'gr' in both C1 and C2
a + 4b = 3a + b
a = 3b/2

C1 in terms of b = 6a = 6 * 3b/2 = 9b

So the ratio of total beads in C1 to C2 would be 9:8 (Ratio Constraint)

and the total number of beads in C1 shall be divisible by 6 to get an integral value and total number of beads in C2 shall be divisible by 8. (Divisibility Constraint)

Only one pair is possible with the ratio constraint and divisibility constraint
C1 = 72 and C2 = 64
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i am going with 72 for c1 and 64 for c2.
c1 ratio 1:2:3, total beads must be a multiple of 6, thus 6x.
c2 ratio 4:1:3 total beads must be a multiple of 8, thus 8y.
1x+4y=3x+1y = y=x
if n=9, c1 = 6x9 = 54
c2 = 8x9 = 72
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Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
given in container 1: Gold : Green: White = 1:3:2,
so, Gold = x
Green = 3x
White = 2x
Total = 6x
similarly in container 2:
Gold = 4y
Green = y
White = 3y
Total = 8y
given, total no of gold beads = total no of green beads
so, x+4y = 3x+y
then, 3y = 2x
\(\frac{x}{y = 3/2 }\)
which we can write as, x = 3k
y = 2k
but we know that in container 1: total no of beads = 6x = 18k
similarly in container 2, total no of beads = 8y = 16k
from the given options, which satisfy the above conditions is for k = 4
then, total no of beads possible in container 1 = 72
similarly, total no of beads possible in container 2 = 64
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Let gold = Go, Green =G , White = W
For Container 1: Ratio Go: G: W= 1:3:2 (let x be the common factor)
For container 2: Ratio= 4:1:3 (let y be the common factore)
A/Q, Total gold bead = total green bead
x+4y = 3x+y
or 2x=3y, or x= 3y/2

Also Container 1 total beads = 6x=9y, container 2 total beads =8y
if y =5
C1= 45, C2=40, but x=3x5/2 not an integer so not possible
if y = 8
C1=72, C2=64 & x=3x8/2
Hence Required possible no of beads for C1 & C2 = 72 & 64 respectively
Hope this helps!


Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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Answer is 72 for container 1 and 64 for container 2, IMO. This is how I calculated it.

Let total beads in first container be x.
So, Gold = x/6; Green = 3x/6 and White = 2x/6

Let total beads in second container be y.
So, Gold = 4y/8; Green = y/8 and White = 3y/8

And given that:
x/6 + 4y/8 = 3x/6 + y/8
x = 9y/8

Hence, x must be a multiple of 9.
However, it should also be multiple of 6, since gold beads = x/6, which must be an integer.

At the same time, x should be chosen in such a way that it satisfies the value of y, when green beads = y/8.

Only 72 and 64 satisfy the above conditions.
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Let the ratio be x: 3x and 2x for container 1

and the ratio be 4y, y and 3y for container 2

As per the question, x + 4y = 3x + 2y. Hence 3y = 2x or x = 3y/2

So total of the container will be 6x and 8y

Replacing with value of x this becomes 9y: 8y so we need the answer in ratio 9: 8

Testing answer choices ---> 72 and 64 suffice.


Bunuel
Clara was assembling display trays using gold, green, and white beads from two containers.


In Container 1, the ratio of gold beads to green beads to white beads was 1 : 3 : 2.

In Container 2, the ratio of gold beads to green beads to white beads was 4 : 1 : 3.

Across the two containers combined, the total number of gold beads was equal to the total number of green beads.

Select for Container 1 the possible total number of beads in Container 1, and select for Container 2 the possible total number of beads in Container 2, that would be jointly consistent with the given information. Make only two selections, one in each column.
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