Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 3001:30 AM EDT
-02:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2912:30 AM EDT
-01:30 AM EDT
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
May 0111:00 AM PDT
-12:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
May 0306:30 AM PDT
-08:30 AM PDT
Verbal trouble on GMAT? Fix it NOW! Join Sunita Singhvi for a focused webinar on actionable strategies to boost your Verbal score and take your performance to the next level.
05 Sep 2024, 03:14
Kudos
Bookmarks
The repair required less than half the average time to complete: True for all chips with spidering
The chip diameter was larger than the median chip diameter.: False for at least one chip with spidering
The insurance reimbursement was greater than or equal to the median insurance reimbursement.: False for at least one chip with spidering
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (02:42) correct
22%
(03:02)
wrong
based on 803
sessions
History
Date
Time
Result
Not Attempted Yet
On a recent workday, a technician repaired one chip—a small area from which a fragment of glass had been broken—in the windshield of each of 9 automobiles. For each automobile, the table indicates the chip’s diameter, in millimeters (mm); whether the chip was accompanied by spidering, which is a pattern of cracks radiating out from the chip; the volume, in milliliters (mL), of sealant used to repair the chip and any accompanying spidering; the time, in hours (h), to complete the repair; and the insurance reimbursement, which is the amount, in US dollars (US$), that was reimbursed by insurance.
For each of the following, select True for all chips with spidering if the given information indicates that the statement is true for each of the 9 chips that was accompanied by spidering. Otherwise, select False for at least one chip with spidering.
| Automobile | Chip diameter (mm) | Spidering? (yes/no) | Volume of sealant used (mL) | Time to complete repair (h) | Insurance reimbursement (US$) |
|---|---|---|---|---|---|
| 1 | 17 | yes | 5 | 0.25 | 45 |
| 2 | 8 | no | 2 | 0.75 | 52 |
| 3 | 24 | yes | 5 | 0.25 | 70 |
| 4 | 5 | no | 1 | 1 | 70 |
| 5 | 17 | yes | 4 | 0.25 | 52 |
| 6 | 17 | no | 3 | 0.75 | 45 |
| 7 | 12 | no | 2 | 1 | 70 |
| 8 | 10 | no | 2 | 0.5 | 70 |
| 9 | 6 | yes | 6 | 0.25 | 52 |
| Average (arithmetic mean) | 12.89 | - | 3.33 | 0.56 | 58.44 |
For each of the following, select True for all chips with spidering if the given information indicates that the statement is true for each of the 9 chips that was accompanied by spidering. Otherwise, select False for at least one chip with spidering.
| True for all chips with spidering | False for at least one chip with spidering | |
| The repair required less than half the average time to complete | ||
| The chip diameter was larger than the median chip diameter. | ||
| The insurance reimbursement was greater than or equal to the median insurance reimbursement. |
ShowHide Answer
Official Answer
The repair required less than half the average time to complete: True for all chips with spidering
The chip diameter was larger than the median chip diameter.: False for at least one chip with spidering
The insurance reimbursement was greater than or equal to the median insurance reimbursement.: False for at least one chip with spidering
Question exposed a gap?
Take sectional Adaptive Quant, Verbal, or DI tests on GMAT Club and review the detailed score report.
Get started →
08 Sep 2024, 01:23
Kudos
Bookmarks
The best way to solve these questions is just have a glance of what is given
Variables and any combined aggregated values
- Variables - Diameter, Volume, Spidering (yes/no), Insurance reibursement
- Aggregated Values - Average
Lets go on option
Who Q is based on spidering - so lets quickly sort the table and any where there is mentioned NO spidering just move on.
Now,
We have 4 spidering options - lazer focus there.
A. Mean is already given in table so we dont need to calculate - great news. For all 4 spidering the time is less than half of mean (0.56/2). Click yes for all
B. Calculate median of all values in column diameter - 5,6,8,10,12,17,17,17,24 - Median is 12. One spidering one doesnt has it greater than 12 but rest do so choose Atleast one column
C. Calculate median of all values in column insurance - 45,45,52,52,52,70,70,70,70 - Median is 52. One spidering one doesnt has it greater than 52 but rest do so choose Atleast one column
Variables and any combined aggregated values
- Variables - Diameter, Volume, Spidering (yes/no), Insurance reibursement
- Aggregated Values - Average
Lets go on option
Who Q is based on spidering - so lets quickly sort the table and any where there is mentioned NO spidering just move on.
Now,
We have 4 spidering options - lazer focus there.
A. Mean is already given in table so we dont need to calculate - great news. For all 4 spidering the time is less than half of mean (0.56/2). Click yes for all
B. Calculate median of all values in column diameter - 5,6,8,10,12,17,17,17,24 - Median is 12. One spidering one doesnt has it greater than 12 but rest do so choose Atleast one column
C. Calculate median of all values in column insurance - 45,45,52,52,52,70,70,70,70 - Median is 52. One spidering one doesnt has it greater than 52 but rest do so choose Atleast one column
23 Sep 2024, 03:37
Kudos
Bookmarks
im not able to understand the question can anbody explain this
