ExplanationInterpret Quantity A
The area of the circle is \(πr^2\)
The area of the inscribed regular hexagon is given as x.
Therefore, Quantity \(A=πr^2−x,\), which is exactly the area
inside the circle but outside the hexagon.
Break that region into congruent pieces. A regular hexagon divides the circle into
6 equal circular segments, one along each side of the hexagon.
Let the area of one such segment be T, then
\(πr^2−x=6T.\)
Relate the shaded region S to one segment
The second polygon is a regular 12-gon.
Each side of the 12-gon subtends
\(\frac{360}{12}=30∘\),
while each side of the hexagon subtends
\(\frac{360}{6}=60∘\),
Since the polygons share six vertices,
each side of the hexagon is replaced by two sides of the dodecagon.
Thus, one hexagon segment is split into
two identical smaller curved regions, one of which is the shaded region S.
Hence,
\(T=2S\)
So
\(πr^2−x=6T=6(2S)=12S\)
Therefore,
- Quantity A =12S
- Quantity B =24S
Since
\(24S>12S\)
Answer: B