I thought about possible
"carry overs", i.e. adding an imaginary digit when you do the written method for addition and a sum of digits is >10.
Ex. 18
+ 23 = 41
Here 8+3=11-> 11 is 1 bigger than 10, so you carry the 1 over to the next "column".
Using this approach let us assess the 2 statements:
(1) No info about hundreds digit, thus insufficient.
(2) Assuming no carry over from the tens to the hundreds digit, the hundreds digit could be 3.
However, assuming a carry over of 1 from the tens to the hundreds digit, the hundreds digit could also be 2. Since more than 1 value for the hundreds digtit is possible, statement (2) is insufficient.
(1) & (2) Using the same reasoning from above, combining the 2 statements does not provide any new information. The hundreds digit could still be 3 or 2.
Hence, the answer is E.
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