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23 Feb 2014, 07:50
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D
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Difficulty:
5%
(low)
Question Stats:
89% (00:51) correct
11%
(01:16)
wrong
based on 1010
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If x, y and z are positive, is x = y/z^2 ?
(1) \(z= \frac{y}{xz}\)
(2) \(z = \sqrt{\frac{y}{x}}\)
(1) \(z= \frac{y}{xz}\)
(2) \(z = \sqrt{\frac{y}{x}}\)
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23 Feb 2014, 07:50
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SOLUTION
If x, y and z are positive, is x = y/z^2 ?
(1) \(z= \frac{y}{xz}\) --> multiply by x/z: \(x=\frac{y}{z^2}\). Sufficient.
(2) \(z = \sqrt{\frac{y}{x}}\) --> square the expression: \(z^2=\frac{y}{x}\) --> \(x=\frac{y}{z^2}\). Sufficient.
Answer: D.
If x, y and z are positive, is x = y/z^2 ?
(1) \(z= \frac{y}{xz}\) --> multiply by x/z: \(x=\frac{y}{z^2}\). Sufficient.
(2) \(z = \sqrt{\frac{y}{x}}\) --> square the expression: \(z^2=\frac{y}{x}\) --> \(x=\frac{y}{z^2}\). Sufficient.
Answer: D.
24 Feb 2014, 03:45
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Option D.
From S1:z=y/xz
Multiply both sides by z,we get
z^2=y/x Or
x=y/z^2.Sufficient.
From S2:Squaring both sides,we get
z^2=y/x
Again cross multiplying,x=y/z^2.Sufficient.
From S1:z=y/xz
Multiply both sides by z,we get
z^2=y/x Or
x=y/z^2.Sufficient.
From S2:Squaring both sides,we get
z^2=y/x
Again cross multiplying,x=y/z^2.Sufficient.
