by: bb
1 hr
by: SwiftMonk
1 hr
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (01:45) correct
30%
(02:10)
wrong
based on 255
sessions
History
Date
Time
Result
Not Attempted Yet
If P and Q are positive integers, is the product 3P^Q divisible by 2?
(1) 6Q^3 + 2 is an even number
(2) P + 8Q^2 is a prime number
_________________
(1) 6Q^3 + 2 is an even number
(2) P + 8Q^2 is a prime number
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
_________________
New to the GMAT Club?
- • Questions: Question Bank | Bunuel's Signature Collection
• Tests: GMAT Club Tests | Forum Quiz
• Guides: Quantitative | Critical Reasoning | Reading Comprehension | Ultimate Quant Guide | All You Need for Quant
• Rules: Quantitative | Verbal
Skywalker18
Retired Moderator
Joined: 08 Dec 2013
Last visit: 15 Nov 2023
Posts: 1,969
Status:Greatness begins beyond your comfort zone
Location: India
Concentration: General Management, Strategy
GPA: 3.2
WE:Information Technology (Consulting)
Products:
Posts: 1,969
3P^Q divisible by 2 if P is even because
3 is odd and does not play a role in making the term even and Q does not effect the even odd nature of the term.
(1) 6Q^3 + 2 is an even number
No information about P is given
Not sufficient.
(2) P + 8Q^2 is a prime number
All prime numbers except 2 are odd .
8Q^2 is even .
Therefore P must be odd .
Sufficient
Answer B
3 is odd and does not play a role in making the term even and Q does not effect the even odd nature of the term.
(1) 6Q^3 + 2 is an even number
No information about P is given
Not sufficient.
(2) P + 8Q^2 is a prime number
All prime numbers except 2 are odd .
8Q^2 is even .
Therefore P must be odd .
Sufficient
Answer B
is 3*P^Q even?
St1: 6Q^3 + even = even --> 6Q^3 = even
Q^3 can be even or odd
No information is given about P
Statement 1 alone is not sufficient
St2: P + 8Q^2 = odd
8Q^2 is even
P = odd - even = odd
Since P is odd, 3P^Q is odd
Statement 2 is sufficient
Answer: B
St1: 6Q^3 + even = even --> 6Q^3 = even
Q^3 can be even or odd
No information is given about P
Statement 1 alone is not sufficient
St2: P + 8Q^2 = odd
8Q^2 is even
P = odd - even = odd
Since P is odd, 3P^Q is odd
Statement 2 is sufficient
Answer: B
douglasvg
Joined: 02 Jun 2015
Last visit: 31 Mar 2017
Posts: 59
Location: Brazil
Concentration: Entrepreneurship, General Management
Schools: Babson '19 (A) Marshall '19 (A)
GPA: 3.3
Schools: Babson '19 (A) Marshall '19 (A)
Posts: 59
1-> We cannot say anything, we don't have the value of P
2-> P + 8Q^2 is a prime number
This means that the number has to be odd
8Qˆ2 is always even.
Therefore P has to be ODD.
Now if we look at the first equation 3P^Q
It doesn't matter how many times we are going to multiple the P, its always going to be Odd:
Odd*Odd=Odd
It means that we cannot divide it by 2
Answer B
2-> P + 8Q^2 is a prime number
This means that the number has to be odd
8Qˆ2 is always even.
Therefore P has to be ODD.
Now if we look at the first equation 3P^Q
It doesn't matter how many times we are going to multiple the P, its always going to be Odd:
Odd*Odd=Odd
It means that we cannot divide it by 2
Answer B
Posts: 2
Here P and Q are positive integers, and we are asked that whether \(3P^Q\) is even or not?
Now we are basically concerned with P i.e. is P even or not?
Because 3 multiplied by even is even and any power to even no. gives you even result.
Statement 1 says: \(6Q^3+2\) is even, but we do not know anything about P.
therefore insufficient.
Statement 2 says : \(P+8Q^2\) is prime.
Now this Prime must be greater than 2, because both P and Q are Positive Integers.
Now, rest all Primes are odd. Therefore,
Odd-\(8Q^2\) will give odd result. Therefore P is Odd.
Therefore sufficient.
Thus, answer is B
Now we are basically concerned with P i.e. is P even or not?
Because 3 multiplied by even is even and any power to even no. gives you even result.
Statement 1 says: \(6Q^3+2\) is even, but we do not know anything about P.
therefore insufficient.
Statement 2 says : \(P+8Q^2\) is prime.
Now this Prime must be greater than 2, because both P and Q are Positive Integers.
Now, rest all Primes are odd. Therefore,
Odd-\(8Q^2\) will give odd result. Therefore P is Odd.
Therefore sufficient.
Thus, answer is B
GMAT 1: 760 Q51 V42
Posts: 10,057
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
If P and Q are positive integers, is the product 3P^Q divisible by 2?
(1) 6Q^3 + 2 is an even number
(2) P + 8Q^2 is a prime number
The question is eventually asking whether P is even as 3 cannot be divided by 2.
From condition 2, p+8Q^2 is told to be prime and this means p is odd, so this answers the question 'no' and is therefore sufficient.
From condition 1, the question is asking whether P is even so this is irrelevant to the question, and insufficient.
The answer therefore becomes (B).
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
If P and Q are positive integers, is the product 3P^Q divisible by 2?
(1) 6Q^3 + 2 is an even number
(2) P + 8Q^2 is a prime number
The question is eventually asking whether P is even as 3 cannot be divided by 2.
From condition 2, p+8Q^2 is told to be prime and this means p is odd, so this answers the question 'no' and is therefore sufficient.
From condition 1, the question is asking whether P is even so this is irrelevant to the question, and insufficient.
The answer therefore becomes (B).
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
_________________
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
_________________
Moderator:
Announcements
How to Tell If Your GMAT Prep Resources Are Actually Helping You
Subscribe to GMAT Club for New Podcast Episodes, Debriefs, & Insightful Sessions on GMAT Preparation
Subscribe to GMAT Club for New Podcast Episodes, Debriefs, & Insightful Sessions on GMAT Preparation
Tuck at Dartmouth
AI at Dartmouth Tuck: How the School Is Preparing Leaders for the Age of Artificial Intelligence
Inside the courses, research, and hands-on learning defining wise, decisive leadership in an AI-driven world.
Read More
Inside the courses, research, and hands-on learning defining wise, decisive leadership in an AI-driven world.
Read More
Top 5 GMAT Debrief Videos
Success stories and strategies from high-scoring candidates.