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02 Sep 2016, 05:23
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
48% (02:37) correct
52%
(02:43)
wrong
based on 120
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of x, if x is an integer?
(1) \(\sqrt{(x+4)*(x-5)} < 11\)
(2) \(\sqrt{(x+4)*(x-5)} > 10\)
(1) \(\sqrt{(x+4)*(x-5)} < 11\)
(2) \(\sqrt{(x+4)*(x-5)} > 10\)
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
hsambiguity
Joined: 09 Jul 2016
Last visit: 07 May 2017
Posts: 22
Given Kudos: 13
Schools: Schulich Sept"19 (A) Rotman '19 (WD)
02 Sep 2016, 06:44
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From Statement 1, squaring both sides
(x+4)(x-5) < 121
x can take any value. Not sufficient.
From Statement 2, squaring both sides
(x+4)(x-5) > 100
x can take any value. Not sufficient.
Combining both, 100< (x+4)(x-5) < 121
Product has to be greater than 100, so we start by checking values of x as x=11,12,13 etc.
when x = 11, (11+4)(11-5)= 90
when x = 12, (12+4)(12-5)=112; Condition satisfied
when x=13, (13+4)(13-5) = 136;
Now x can also be negative
Checking for -11, (-11+4)(-11-5) = 112; Condition satisfied
So, value of x could be 12 or -11. Hence answer is E
(x+4)(x-5) < 121
x can take any value. Not sufficient.
From Statement 2, squaring both sides
(x+4)(x-5) > 100
x can take any value. Not sufficient.
Combining both, 100< (x+4)(x-5) < 121
Product has to be greater than 100, so we start by checking values of x as x=11,12,13 etc.
when x = 11, (11+4)(11-5)= 90
when x = 12, (12+4)(12-5)=112; Condition satisfied
when x=13, (13+4)(13-5) = 136;
Now x can also be negative
Checking for -11, (-11+4)(-11-5) = 112; Condition satisfied
So, value of x could be 12 or -11. Hence answer is E
02 Sep 2016, 20:55
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1: (x+4)(x-5)<121
or x(x-1)<141 not sufficient as there are many values of x satisfying the equation
2: x(x-1)>120 not sufficient
1 and 2 :
120<x(x-1)<141
x= -11 and 12 both satisfy
hence E
or x(x-1)<141 not sufficient as there are many values of x satisfying the equation
2: x(x-1)>120 not sufficient
1 and 2 :
120<x(x-1)<141
x= -11 and 12 both satisfy
hence E
