Is ab < 0?
When one is asked if the product of two variables (i.e.: a and b) is negative one is asked whether the variables display contrary signs (that is (a > 0 and b < 0) or (a < 0 and b > 0)).
From (1), a^4 and c^2 must be greater than zero regardless of their absolute value since their power is even whereas b has an odd exponent yielding a negative value => b < 0!
However, it is not really interesting as we cannot still infer anything about the sign of a.
Hence, S1 is INSUFFICIENT.
From (2), since (bc)^6 must be positive it comes that a is also positive => a > 0.
Again, the rationale behind is the same (bc)^6 is positive but we cannot infer anything about the direction of B.
Hence, S2 is INSUFFICIENT.
Combining S1(b<0) and S2 (a>0) together, it follows that:
(-) * (+) < 0 - TRUE proposition.
Hence S1 and S2 together are sufficient to answer if ab < 0!
Hope it helps,
Gonçalo