|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
10 Sep 2017, 09:20
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:13) correct
20%
(01:16)
wrong
based on 123
sessions
History
Date
Time
Result
Not Attempted Yet
Consider three real numbers, \(x\), \(y\), and \(z\). Is \(z\) the smallest of these numbers?
A. \(x\) is greater than at least one of \(y\) and \(z\)
B. \(y\) is greater than at least one of \(x\) and \(z\)
A. \(x\) is greater than at least one of \(y\) and \(z\)
B. \(y\) is greater than at least one of \(x\) and \(z\)
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
10 Sep 2017, 11:30
Kudos
Bookmarks
Consider three real numbers, x, y, and z. Is z the smallest of these numbers?
A. x is greater than at least one of y and z
B. y is greater than at least one of x and z
Statement 1: x is greater than at least one of y and z
So, x> y or x >z but it is not clear y>z or z>y, -> Insufficient.
Statement 2: y is greater than at least one of x and z.
So y>x or y>z but it is not clear x>z or z>x. -> insufficient.
1+2 we can consider x>z and y>z -> Sufficient.
Answer: C
If I am wrong kindly correct me.
A. x is greater than at least one of y and z
B. y is greater than at least one of x and z
Statement 1: x is greater than at least one of y and z
So, x> y or x >z but it is not clear y>z or z>y, -> Insufficient.
Statement 2: y is greater than at least one of x and z.
So y>x or y>z but it is not clear x>z or z>x. -> insufficient.
1+2 we can consider x>z and y>z -> Sufficient.
Answer: C
If I am wrong kindly correct me.
12 Sep 2017, 08:16
Kudos
Bookmarks
niks18
OE
Statement A: implies \(x>y\) or \(x>z\) or \(x>y\) and \(z\). Hence Insufficient
Statement B: implies \(y>x\) or \(y>z\) or \(y>x\) and \(z\). Hence Insufficient
Combining both statements, we can get \(y>x >z\) or \(x>y>z\). In either case \(z\) is the smallest.
Option C
