amanvermagmat
X, Y, Z are integers. Is 3*X > Z?
(1) X + 2*Y > 3*Z
(2) 2*Z > 2*Y - X
As all we're given is equations, we'll work with equation-related tools such as simplification.
This is a Precise approach.
(1) Multiplying our inequality by 3 gives 3x+6y>9z --> 3x > 9z - 6y.
Without knowing if y is positive or negative we definitely cannot know if 3x > 9z, let alone 3x>z.
Insufficient.
(2) We'll once again try to create "3x is larger than" in our expression: Multiplying by 3 gives
6z>6y-3x --> 3x>6y-6z. Similarly to the before, we need some information about y to solve.
Insufficient.
Combined.
We'll notice that one equation has '6y' and another has '-6y'. Adding them together cancels out the y and gives
3x+3x > (3z-6y)+(6y-9z) --> 6x > -6z --> 3x > -3z.
So, to answer the question we need to know if -3z > z. But is it? If z is positive this inequality is always false and if it is negative this inequality is always true.
Insufficient.
(E) is our answer.