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555-605 (Medium)|   Geometry|      
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If rectangle ABCD can be divided into two equal squares, what is the 04 Sep 2018, 23:42
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If rectangle ABCD can be divided into two equal squares, what is the perimeter of rectangle ABCD?

(1) AB = 10
(2) The sum of the perimeters of the two squares that be formed by dividing rectangle ABCD is 40.

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If rectangle ABCD can be divided into two equal squares, what is the 04 Sep 2018, 23:53
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Bunuel

If rectangle ABCD can be divided into two equal squares, what is the perimeter of rectangle ABCD?

(1) AB = 10
(2) The sum of the perimeters of the two squares that be formed by dividing rectangle ABCD is 40.

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(1) AB = 10
length of each side of the square =5
perimeter of each square = 4*5 =20
perimeter of rectangle = 2*perimeter of square = 40
sufficient

(2) The sum of the perimeters of the two squares that be formed by dividing rectangle ABCD is 40.
sum of perimeter of two squares = perimeter of the rectangle = 40
Sufficient

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If rectangle ABCD can be divided into two equal squares, what is the 06 Oct 2018, 22:50
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Answer should be B.
We do not know which one is greater side AB or CD.
Now if AB is smaller then to divide it in a two square CD has to be 20 and if AB is greater then CD has to be 5.
So statement 1 is not sufficient.

Now to talk about statement 2 we know that summation of perimeters of two squares is 40 lets say the side is a so total perimeter will be 8a. So statement 2 is sufficient to determine the perimeter of the rectangle
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If rectangle ABCD can be divided into two equal squares, what is the 07 Oct 2018, 00:55
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LoneSurvivor
Answer should be B.
We do not know which one is greater side AB or CD.
Now if AB is smaller then to divide it in a two square CD has to be 20 and if AB is greater then CD has to be 5.
So statement 1 is not sufficient.

Now to talk about statement 2 we know that summation of perimeters of two squares is 40 lets say the side is a so total perimeter will be 8a. So statement 2 is sufficient to determine the perimeter of the rectangle
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We need to go by the figure here , and by the figure AB is clearly the longer side .
Now for sure AD can vary between > 0 and < 10
but from statement 1 the only way to divide a rectangle into two equal squares is by bisecting the longer side.
This tells us that AD=5 and the statement is sufficient.
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If rectangle ABCD can be divided into two equal squares, what is the 07 Oct 2018, 03:10
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Answer should be B.
We do not know which one is greater side AB or CD.
Now if AB is smaller then to divide it in a two square CD has to be 20 and if AB is greater then CD has to be 5.
So statement 1 is not sufficient.

Now to talk about statement 2 we know that summation of perimeters of two squares is 40 lets say the side is a so total perimeter will be 8a. So statement 2 is sufficient to determine the perimeter of the rectangle


We need to go by the figure here , and by the figure AB is clearly the longer side .
Now for sure AD can vary between > 0 and < 10
but from statement 1 the only way to divide a rectangle into two equal squares is by bisecting the longer side.
This tells us that AD=5 and the statement is sufficient.
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You can not assume it from figure that which one is greater and if it was not mentioned that ABCD is a rectangle we are not supposed to take it as rectangle just because it looks like so
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If rectangle ABCD can be divided into two equal squares, what is the 07 Oct 2018, 05:12
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LoneSurvivor
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Answer should be B.
We do not know which one is greater side AB or CD.
Now if AB is smaller then to divide it in a two square CD has to be 20 and if AB is greater then CD has to be 5.
So statement 1 is not sufficient.

Now to talk about statement 2 we know that summation of perimeters of two squares is 40 lets say the side is a so total perimeter will be 8a. So statement 2 is sufficient to determine the perimeter of the rectangle


We need to go by the figure here , and by the figure AB is clearly the longer side .
Now for sure AD can vary between > 0 and < 10
but from statement 1 the only way to divide a rectangle into two equal squares is by bisecting the longer side.
This tells us that AD=5 and the statement is sufficient.

You can not assume it from figure that which one is greater and if it was not mentioned that ABCD is a rectangle we are not supposed to take it as rectangle just because it looks like so
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Absolutely my friend !!
The only reason I wrote that was because it was mentioned that the figure is a rectangle .
Since it is a rectangle , one side has to be greater than the other and the figure shows which side is greater !!
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