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Is quadrilateral XYZW a rhombus?
(1) Diagonals of quadrilateral XYZW intersect at 90 degrees.
(2) X, Y, Z, W are the mid-points of sides AB, BC, CD and DA respectively of a rectangle ABCD.
Solution
Step 1: Analyse Question Stem
• XYZW is a quadrilateral
We need to find whether XYZW is a rhombus or not.
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: Diagonals of quadrilateral XYZW intersect at 90 degrees
• We don't know whether all the sides of XYZW are equal or not
• We know that the diagonals of kite, square and rhombus intersect each other at 90 degree
o XYZW can be a kite, rhombus, or square
Hence, statement 1 is not sufficient, we can eliminate the answer options A and D.
Statement 2: X, Y, Z, and W are the midpoints of the sides AB, BC, CD, and DA, respectively of the rectangle ABCD.
Let 2l and 2b be the length and breadth of the rectangle ABCD.

• \(XY = YZ = ZW=ZW = \sqrt{l^2+b^2}\)
o All the sides of the XYZW are equal.
• Diagonals of XYZW are parallel to the sides of ABCD
o XZ is parallel to BC and AD
o YW is parallel to AB and CD
XZ and YW bisect each other perpendicularly.
• Thus, XYZW is a rhombus
Hence, statement 2 is sufficient, the correct answer is
Option B.