(1) The edge of one of the cubical boxes is 4/5 as wide as the diameter of the cylinder.
The diagonal of the square will be the diameter of the circle (base of the cylinder). diameter = s*(2)^0.5
Edge of the cube is (4/5)*d
(4/5)*d * \(\sqrt{2}\) is greater than d, so doesnt make sense.
This is enough to prove that the cubes cannot fit in the cylinder.
(2) If the cylinder had 50% more capacity, seven of the identical cubical boxes could fit inside the cylinder
Capacity can be increased by increasing the surface area of the base of cylinder or the height of the cylinder or both. We can say that 3 cubes will fit in if only one of height or base has been increased since 7 can fit in if capacity is increased by 50%. However if both have been increased then we cannot say for sure. Hence (2) is not sufficient.
So, the answer should be A.