We are to determine the unit digit of 3^(4x+2y+6) given that x and y are positive integers.
3^(4x+2y+6) = 3^4x * 3^2y * 3^6
We know that the cyclicity of 3 is 4. Hence the value of x is irrelevant since it will always lead to the same unit digit. In addition, 3^6 has the same unit digit as 3^2 = 9. 3^2y, on the other hand, is not fixed. when y is odd, then 3^2y has the same cyclicity as 3^2. When y is even however, 3^2y has the same cyclicity of 3^4, hence we need the value of y in order to determine the unit digit of 3^(4x+2y+6).
Statement 1: x=1
This is insufficient. We need only the value of y since the value of x is immaterial to the determination of the unit digit of 3.
Statement 2: y=2
This is sufficient since we have been provided the only missing piece of the puzzle, which is the value of y. We now know that 3^(4x+2y+6) has the same unit digits as 3^2 = 9.
The answer is therefore B.