Analyzing the question:Given n can be 1, 2, 3 ... 8, 9.
Is n equal to either 2, 3, 5, or 7?
Statement 1:For a decimal to terminate, we cannot divide by 3 or any prime number greater than 6.
If 1/n is terminating we can choose n = 1, 2, 4, 5, 8. Out of these n = 2 and n = 5 are prime but the rest aren't, so insufficient.
Statement 2:We can get a decimal that terminates but has 3 or more digits on the right of the decimal point, or simply a decimal that doesn't terminate.
n = 3, 6, 7, 9 are nonterminating.
n = 8 gives 3 digits. Out of these n = 3 and n = 7 are prime but the rest aren't, insufficient.
Combined:n = 8 is the only common number in both, sufficient.
Ans: C
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