a, b, c, d, e What is the value of median of list of integers above if

Question

a, b, c, d, e
What is the value of median of the list of integers above if a < b < c < d < e

(1) The range of the list is 4
(2) Sum of the integers in the list is 0

IanStewart · Answer

If, as we're told, the five letters are listed in increasing order, then c is the median, so we just want to know if we can find the value of c.

Statement 1 tells us the range is 4. The only way a list of five different integers can have a range of 4 is if the integers are consecutive. But we don't know how big they are, so we can't find the value of c.

Statement 2 is not sufficient alone - the list could be -2, -1, 0, 1, 2, say, and then c = 0, but it could be -1000, 100, 200, 300, 400, say, and then c = 200.

Using both Statements: we know from Statement 1 that our list is equally spaced, so the mean and median are equal. Statement 2 tells us the sum of the list is zero, so its mean is zero, and since the list is equally spaced, so is its median. So the answer is C.

Kinshook · Answer

Given: a, b, c, d, e Asked: What is the value of median of the list of integers above if a < b < c < d < e (1) The range of the list is 4 e-a = 4 - > e = d+1 = c+2 = b+3 = a + 4; Since all are integers Median = c = a + 2 = e - 2 But there is no information about absolute value of any number. NOT SUFFICIENT (2) Sum of the integers in the list is 0 a + b + c + d + e = 0 Median = c If (a,b,c,d,e) = (-2,-1,0,1,2); Median = c = 0 But if (a,b,c,d,e) = (-4,-3,-2,-1,10); Median = c = -2 NOT SUFFICIENT (1) + (2) (1) The range of the list is 4 e-a = 4 - > e = d+1 = c+2 = b+3 = a + 4; Since all are integers (2) Sum of the integers in the list is 0 a + b + c + d + e = 0 c-2 + c - 1 + c + c+ 1 + c + 2 = 0 5c = 0; c= 0 = Median SUFFICIENT IMO C

Archit3110 · Answer

#1
The range of the list is 4
we can have 
-1,0,1,2,3
or 1,2,3,5
insufficient to determine mean
#2
Sum of the integers in the list is 0
again there can be many possiblities of getting mean 
 -6,0,1,2,3 or -2,-1,0,1,2
insufficient
from 1 &2
set is -2,-1,0,1,2
sufficient
OPTION C

minustark · Answer

1) From this statement we can infer that a, b, c, d, e are 5 consecutive integers. The median will be the value of c. But we have no other information. Not sufficient.

2) Lets take, -3, -2, -1, 2, 4, where the median is -1. Again, for -2, -1, 0, 1, 2, the median is 0. Not sufficient.

Together, the only possible set of integers is -2, -1, 0, 1, 2. Sufficient.

C is the answer

ueh55406 · Answer

a, b, c, d, e

a < b < c < d < e

(1) The range of the list is 4 -- e-a= 4 -- NS.
(2) Sum of the integers in the list is 0 -- NS.

1+2

range is 4 and sum is zero, only possible series :-  -2, -1 , 0, 1, 2

median= 0

Sufficient.

bumpbot · Answer

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a, b, c, d, e What is the value of median of list of integers above if

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