Last visit was: 13 Sep 2026, 04:27 It is currently 13 Sep 2026, 04:27
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 13 Sep 2026
Posts: 113,481
Own Kudos:
Given Kudos: 111,490
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,481
Kudos: 840,977
 [16]
2
Kudos
Add Kudos
14
Bookmarks
Bookmark this Post
avatar
KumarSri
Joined: 24 Feb 2019
Last visit: 14 Apr 2022
Posts: 82
Own Kudos:
92
 [1]
Given Kudos: 18
Posts: 82
Kudos: 92
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
zhanbo
Joined: 27 Feb 2017
Last visit: 07 Jul 2024
Posts: 1,463
Own Kudos:
2,491
 [2]
Given Kudos: 114
Location: United States (WA)
GMAT 1: 760 Q50 V42
GMAT 2: 760 Q50 V42
GRE 1: Q169 V168
GRE 2: Q170 V170
Expert
Expert reply
GMAT 2: 760 Q50 V42
GRE 1: Q169 V168
GRE 2: Q170 V170
Posts: 1,463
Kudos: 2,491
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Gmatfox
Joined: 09 Jan 2015
Last visit: 10 Sep 2026
Posts: 11
Own Kudos:
34
 [2]
Given Kudos: 7
Posts: 11
Kudos: 34
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is the perimeter of a rectangle more than 60 cm ?

(1) The area of the rectangle is 226 cm^2.
(2) The length of a diagonal of the rectangle is 30 cm.

L + W > 30 Y/N?


1) Area = 226 = LxW

We have (L+W)^2 >= 4LW = 4x226 > 4x225 = (2x15)^2 --> L + W > 30 --> Yes --> Sufficient
Notice that: (L+W)^2 >= 4LW or (L-W)^2 >= 0 is always true


2) Diagonal = 30

Let's consider half of that rectangle, we will have L + W > Diagonal = 30 (according to side inequalities in a certain triangle)
--> Yes --> Sufficient

Correct answer: D
User avatar
bidskamikaze
Joined: 07 Jan 2018
Last visit: 29 Oct 2022
Posts: 251
Own Kudos:
314
 [1]
Given Kudos: 160
Location: India
GMAT 1: 710 Q49 V38
GMAT 1: 710 Q49 V38
Posts: 251
Kudos: 314
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is the perimeter of a rectangle more than 60 cm ?

(1) The area of the rectangle is 226 cm^2.

Concept: For a given area of quadrilateral, a square would have the smallest perimeter.
So, let us assume that the rectangle is actually a square.
If area (of square) = 226, side = 15.033 (approx)
So the perimeter would be slightly greater than 60 cm.
If a square has a greater perimeter than 60, a rectangle would definitely have a perimeter > 60
Sufficient.


(2) The length of a diagonal of the rectangle is 30 cm.

If length = l and Breadth = b
\(l^2 + b^2\) = 900
Suppose: b= 20, then l= 22.36. (perimeter 84.72 > 60)
Suppose: b= 10, then l= 28.28. (perimeter 76.56 > 60)
Suppose: b= 1, then l= 29.98. (perimeter 61.96 > 60)
Now Suppose b = 0.0001, then l = 29.9999983333 (perimeter 60.000196 > 60)
As one of the sides gets smaller and smaller, the perimeter gets closer to 60.
HOWEVER, the perimeter will ALWAYS be > 60,
This is also sufficient

Both statements individually sufficient.
Answer D
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 13 Sep 2026
Posts: 113,481
Own Kudos:
Given Kudos: 111,490
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,481
Kudos: 840,977
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
12 Days of Christmas GMAT Competition with Lots of Fun

Is the perimeter of a rectangle more than 60 cm ?

(1) The area of the rectangle is 226 cm^2.
(2) The length of a diagonal of the rectangle is 30 cm.




M36-92

Official Solution:


Is the perimeter of a rectangle more than 60 cm ?

(1) The area of the rectangle is 226 cm^2.

Given \(ab = 226\).

Now, for rectangles with a fixed area, a square has the minimum perimeter. So, the minimum perimeter will occur when \(a=b\). In this case, we'd have \(a^2=226\).

\(a=15.something\) and thus the perimeter is \(4*15.something=60.something>60\). As even the minimum possible perimeter is more than 60 cm, then the actual perimeter, whatever it is, is also more than 60 cm. Sufficient.

(2) The length of a diagonal of the rectangle is 30 cm.

The diagonal, the length and the width of a rectangle form a triangle and in a triangle the length of any side must be smaller than the sum of the other two sides. So, \(a+b>30\) and thus \(perimeter=2(a + b) > 60\) Sufficient.


Answer: D
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 39,230
Own Kudos:
Posts: 39,230
Kudos: 1,158
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderator:
Math Expert
113481 posts