Bunuel
If y is positive, is \(y^x > 1000\)?
(1) \(y^x = 3000 + y^{(x –1)}\)
(2) \(x > 1000\)
Given: y is positive Target question: Is \(y^x > 1000\)? Statement 1: \(y^x = 3000 + y^{(x –1)}\)Key property: If \(y\) is positive, then \(y^x > 0\) for all values of \(x\)This means statement 1 is actually telling us that: \(y^x = 3000 + \)
some positive value, which means \(y^x > 3000\)
If \(y^x > 3000\), then we can be certain that
\(y^x > 1000\)Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: \(x > 1000\)There are several values of x and y that satisfy statement 2. Here are two:
Case a: \(y = 1\) and \(x = 2000\). Since \(1^{2000} = 1\), the answer to the target question is
NO, \(y^x\) is not greater than \(1000\)Case b: \(y = 10\) and \(x = 2000\). In this case, we can clearly see that
\(10^{2000}\) is definitely greater than \(1000\)Since we can’t answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: ACheers,
Brent