|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
13 Sep 2022, 21:49
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
90% (01:11) correct
10%
(01:15)
wrong
based on 49
sessions
History
Date
Time
Result
Not Attempted Yet
Is integer k divisible by 5 ?
(1) 24k is divisible by 20
(2) k + 1 is divisible by 6
(1) 24k is divisible by 20
(2) k + 1 is divisible by 6
|
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
13 Sep 2022, 23:12
Kudos
Bookmarks
Bunuel
Solution:
Pre-Analysis:
- We are asked if an integer k is divisible by 5 or not
- This is a yes-no question
Statement 1: 24k is divisible by 20
- Accoridng to this statement \(24k=20p\) where p is a positive integer
- Which means we can say \(p=\frac{24k}{20}=\frac{2^3\times 3\times k}{2^2\times 5}=\frac{2\times 3\times k}{5}\)
- Now \(p=\frac{2\times 3\times k}{5}\) is a positive integer only and only if k is divisible by 5
- Thus, statement 1 alone is sufficient and we can eliminate options B, C and E
Statement 2: k + 1 is divisible by 6
- Let's take two cases:
- Case 1: \(k+1=6\) (divisible by 6), then \(k=5\) is divisible by 5
- Case 2: \(k=12\) (divisible by 6), then \(k=11\) is not divisible by 5
- Thus, statement 2 alone is not sufficient
Hence the right answer is Option A
13 Sep 2022, 23:24
Kudos
Bookmarks
The working is shown in the attached image.
Option A
Option A
Attachments
Screenshot 2022-09-14 115314.png [ 75.09 KiB | Viewed 1266 times ]
