Bunuel
Is |x| + x > |y| + y ?
(1) x > y
(2) Both x and y are negative
Statement 1 x > yCase 1:
------- 0 ---------- y -------- x ----------
Is (the distance of x from 0 + the value of x) > (the distance of y from 0 + the value of y) -- Yes !
Case 2:
------- y ---------- x -------- 0 ----------
Is (the distance of x from 0 + the value of x) > (the distance of y from 0 + the value of y) -- No !
|x| + x = |y| + y = 0
The statement is not sufficient. Hence eliminate A and D.
Statement 2 Both x and y are negativeIf both x and y are negative |x| + x = |y| + y = 0.
Hence we have a definite answer to the question
Is (the distance of x from 0 + the value of x) > (the distance of y from 0 + the value of y) -- No !
Sufficient
Option B
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