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Updated on: 11 Jul 2013, 02:29
Originally posted by burnttwinky on 19 Jan 2010, 22:04.
Last edited by Bunuel on 11 Jul 2013, 02:29, edited 1 time in total.
Last edited by Bunuel on 11 Jul 2013, 02:29, edited 1 time in total.
Edited the question and added the OA
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
60% (02:00) correct
40%
(02:32)
wrong
based on 419
sessions
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Not Attempted Yet
In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangular region RCS ?
(1) The area of triangular region ABX is 32.
(2) The length of one of the altitudes of triangle ABC is 8.
OPEN DISCUSSION OF THIS QUESTION IS HERE: in-triangle-abc-point-x-is-the-midpoint-of-side-ac-and-82671.html
(1) The area of triangular region ABX is 32.
(2) The length of one of the altitudes of triangle ABC is 8.
OPEN DISCUSSION OF THIS QUESTION IS HERE: in-triangle-abc-point-x-is-the-midpoint-of-side-ac-and-82671.html
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gurpreetsingh
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19 Jan 2010, 22:27
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IMO ans should be A.
Area of triangle ABX = area of BXC as median divides the triangle into 2 equal areas.
similarly area of XYC = 1/2 BXC = ( 1/2 ABX) = 1/2 * 32 = 16
Now XYC and RSC are similar triangles
Since we have area of XYC , we can find the area of triangle RSC.
Thus statement 1 is sufficient.
Statement 2 seems not sufficient, not enough parameters given.
ANS - A.. OA please.
Area of triangle ABX = area of BXC as median divides the triangle into 2 equal areas.
similarly area of XYC = 1/2 BXC = ( 1/2 ABX) = 1/2 * 32 = 16
Now XYC and RSC are similar triangles
Since we have area of XYC , we can find the area of triangle RSC.
Thus statement 1 is sufficient.
Statement 2 seems not sufficient, not enough parameters given.
ANS - A.. OA please.
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19 Jan 2010, 22:57
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You are correct. The official answer is A.
