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14 Sep 2003, 04:59
Kudos
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N
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We have 1.5 mins....Lets go!
The owner of an art shop conducts his business in the following
manner: Every once in a while he raises his prices by X%, then a while
later he reduces all the new prices by X%. After one such up-down cycle,
the price of a painting decreased by Rs 441. After a second up-down cycle
the painting was sold for Rs 1944.81. What was the original price of the
painting?
a) 2756.25
b) 2256.25
c) 2500
d) 2000
explain at leisure!
thanks
praetorian
The owner of an art shop conducts his business in the following
manner: Every once in a while he raises his prices by X%, then a while
later he reduces all the new prices by X%. After one such up-down cycle,
the price of a painting decreased by Rs 441. After a second up-down cycle
the painting was sold for Rs 1944.81. What was the original price of the
painting?
a) 2756.25
b) 2256.25
c) 2500
d) 2000
explain at leisure!
thanks
praetorian
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16 Sep 2003, 23:54
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lazerbud
The "441" solves 99% of the problem in 30 seconds....but just to give you a explanation..here goes
1st equation
Let SP be original selling price
SP*(1+ X/100) (1-X/100) = SP-441
2nd Equation
(SP-441) * (1+X/100)(1-X/100) = 1944.81 .....eqn 2
Now, from 1... (1+ X/100) (1-X/100) = SP-441 /SP
Therefore
(SP -441) * (SP-441) /SP[b]= 1944.81 .....equation 3
[b]Some Common Sense
Look at the answer choices...it cant be 2000 and 2256..because the first "round" itself reduces the price by 441 which will be less than 1944.81...so these two are incorrect.
Also 2500 gets reduced to 2059 in the first "round ".....its too close to 1944.81 in the first round itself...but just to be sure..
We'll try the largest value 2756.25 ..Lets approximate SP to 2800
and 441 to 500 ...cool? ok
(2800-500)*(2800-500) /2800 = 2300 *23/28 =52900/28 => 1889
Thats as close as you can get in 45 seconds..
Answer A
comments?
thanks
praetorian
