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For positive integers p and q, p/q when expressed as a decimal, is a t
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13 Oct 2018, 09:14
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56% (02:52) correct 44% (02:28) wrong based on 43 sessions
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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Updated on: 13 Oct 2018, 09:33
For positive integers p and q, p/q when expressed as a decimal, is a terminating decimal? (1) p is the sum of three consecutive odd multiples of 5. (2) 2q2+144=36q2q2+144=36q
For a decimal to be terminating the denominator must be a multiple of 5 or 2 in its base form.. from A p is of the form 15(2n+3) ...45,75,105.... so its in sufficient from B we know q can be 12 or 6... but cannot be sure if the reduced form of fraction will have only 2 or 5 hence insufficient
From A & B we know P is multiple of 3....so if q is 6 or 12 then the fraction will will have denominator of the form 2 hence termination hence answer is C
Originally posted by swapnil611 on 13 Oct 2018, 09:19.
Last edited by swapnil611 on 13 Oct 2018, 09:33, edited 1 time in total.



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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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13 Oct 2018, 09:22
From statement 1: P is the sum of three consecutive odd multiples of 5. P will be 45n+30. therefore P is odd. But terminating decimal depends on the denominator. A decimal will be terminating only if the denominator consists only of 2s or 5s. Hence 1 is insufficient. From statement 2: Solving for q gives q = 12 or 6. Both contain 3 as a factor. Hence We need the value of P. 2 is insufficient. Combining both: If p = 45 and q =12 then p/q is terminating. even when q =6. So combining works. C is the answer.
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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13 Oct 2018, 09:23
I feel Option (C) should be correct, please find my solution attached. Regards, Gladi
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For positive integers p and q, p/q when expressed as a decimal, is a t
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Updated on: 13 Oct 2018, 20:11
1) Value of p may be 5, 15, 25, and likewise. This says nothing about q( sum 5+15+25=45)Now 45/11 may be non terminating while 45/6 is terminating, Hence NOT SUFFICIENT2) Value of q may be 12 or 6 upon solving the quadratic equation. (15/6 is non terminating, while 15/12 is terminating) , Hence this too is NOT SUFFICIENTBut when we take both statements together, It becomes sufficient as 45/6 or 45/12 is ALWAYS terminating. Hence 1) and 2) together are SUFFICIENTHence the C should be correct
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Originally posted by saurabh1921 on 13 Oct 2018, 09:25.
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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13 Oct 2018, 09:34
For positive integers p and q, p/q when expressed as a decimal, is a terminating decimal? (1) p is the sum of three consecutive odd multiples of 5. (2) 2q2+144=36q2q2+144=36q IMO C is right. Stmnt 1; sum 5+15+25=45 stmnt 2: quadratic we get q= 12,6 45/12= 3.75 and 45/6=7.5 C should be correct
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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13 Oct 2018, 09:46
(1) p is the sum of three consecutive odd multiples of 5.  NS ( no info for q) (2) 2q^2+144=36q NS (no info for p) 2q^2+144=36q ==> q^218Q+72=0 => (q6)(q12)=0 ==> q=2*3 or 4*3 1+2) Suff..........p= 5(2a+1)+5(2a+3)+5(2a+5)=30a+45 = 3(10a+15) has a factor of 3 and others of q could only be 2 or 4.... thus p/q terminatic decimal Ans C
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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13 Oct 2018, 09:48
Statement 1 : p is the sum of three consecutive odd multiples of 5.
p could be { 5+10+15 = 30 } or { 10+15+20 = 45} This doesn't given us anything about q so===> it is insufficient
Statement 2 : this quadratic equation gives us q as values 12 and 6
doent give us anything about value of p so this alone is insufficient
Both considered together ==> so when lets say p = 12 , q = 30
==> p/q = 12/30 is finite
but when q = 45 , p/q is not finite ... so both together is also insufficient ==> OA is E



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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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14 Oct 2018, 01:07
swapnil611 wrote: For positive integers p and q, p/q when expressed as a decimal, is a terminating decimal? (1) p is the sum of three consecutive odd multiples of 5. (2) 2q2+144=36q2q2+144=36q
For a decimal to be terminating the denominator must be a multiple of 5 or 2 in its base form.. from A p is of the form 15(2n+3) ...45,75,105.... so its in sufficient from B we know q can be 12 or 6... but cannot be sure if the reduced form of fraction will have only 2 or 5 hence insufficient
From A & B we know P is multiple of 3....so if q is 6 or 12 then the fraction will will have denominator of the form 2 hence termination hence answer is C Hi, How have you reduced A) to 15(2n+3)? shouldn't it be 5*n+5*(n+2)+5*(n+4) = 5(n+n+2+n+4) = 5(3n+6) = 15(n+2) ?
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For positive integers p and q, p/q when expressed as a decimal, is a t
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14 Oct 2018, 01:17
I assumed numbers as 5×(2n +1),5×(2n+3),5×(2n+5) hence the sum 5×(6n+9)=15(2n+3)...If you assume number as n it can be both even or odd but in the question it's mentioned odd multiple of 5. Hope am clear
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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19 Feb 2019, 16:09
Can someone please explain why only fractions with denominators of 2 or 5 are terminating? Thanks....



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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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19 Feb 2019, 19:22
Hi You can observe that if the numerator is not a multiple of denominator and denominator is multiple of 3,7 or any number other than 2 or 5, the result will be non terminating decimals. For example: 1/3 = 0.333333333333... 1/7 = 0.1428571428... RichardSaunders wrote: Can someone please explain why only fractions with denominators of 2 or 5 are terminating? Thanks.... Posted from my mobile device
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Re: For positive integers p and q, p/q when expressed as a decimal, is a t
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