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# Weird DS from Princeton

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Manager
Joined: 09 Nov 2006
Posts: 128

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10 Jan 2007, 07:29
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I think that explanation is wrong. C can't be 10 and D can't be 9, bcoz initial terms say that C<D, therefore B must be sufficient?
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SVP
Joined: 01 May 2006
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10 Jan 2007, 10:51
AdrianG, I think u are right .... The answer should be B

90 = 3 *3 * 2 * 5

Stat 1
o If c=9 and d = 10, then d-c = 1
o If c=3 and d = 30, then d-c = 29

INSUFF.

Stat 2
Consecutive integer and c < d implies only 1 solution c = 9 and d = 10

SUFF.

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VP
Joined: 21 Mar 2006
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Location: Bangalore

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10 Jan 2007, 20:37
Fig wrote:
AdrianG, I think u are right .... The answer should be B

90 = 3 *3 * 2 * 5

Stat 1
o If c=9 and d = 10, then d-c = 1
o If c=3 and d = 30, then d-c = 29

INSUFF.

Stat 2
Consecutive integer and c < d implies only 1 solution c = 9 and d = 10

SUFF.

Agree. The stem itself states that c<d. So if c and d are consecutive positive integers AND cd =90, the only possible combination is c = 9 and d = 10.

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VP
Joined: 15 Jun 2006
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11 Jan 2007, 00:12

Where did you take this example from? Doesn't look like a GMATPrep interface.

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Manager
Joined: 09 Nov 2006
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11 Jan 2007, 00:44
Helg, haven't you heard about Princeton Review?

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11 Jan 2007, 00:44
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