Rule 1: the "Foot" of the Perpendicular from Point (2 , 2) to the Line given by y - 2x - 8 = 0 will be the Point at which the Line connected to (2 , 2) will be PERPENDICULAR to the Line given by y - 2x - 8 = 0
Rule 2: the Slop of a Perpendicular Line is the (-)Neg. Reciprocal of the Original Line's Slope
y - 2x - 8 = 0
In Slope Intercept Form:
y = 2x + 8
Slope = m = +2
The (-)Negative Reciprocal of +2 ----- (-)1/2
Thus, the Perpendicular Line must be of the Form: y = (-)1/2x + b
We know that this Line must Intersect Point (2, 2). So we can Plug this Point into the Equation to find the Y-Intercept = b
y = (-)1/2x + b
2 = (-)1/2 * (2) + b
2 = -1 + b
b = 3
The Equation of the Line: y = -1/2x + 3
Finally, we can find the exact Point by setting the 2 Equations Equal and Find the X-Coordinate of their Intersection
y = 2x + 8 = -1/2x + 3 = y
4x + 16 = -1x + 6
5x = -10
x = -2
The Y-Coordinate is given as, after plugging in x = -2:
y = -1/2 * (-2) + 3
y = 4
The Answer is: (X , Y) = (-2 , 4)
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