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What is 2^2*4^4*8^8?

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Joined: 02 Sep 2009
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What is 2^2*4^4*8^8? [#permalink]

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New post 21 Feb 2017, 05:35
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

97% (00:22) correct 3% (00:21) wrong based on 45 sessions

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Re: What is 2^2*4^4*8^8? [#permalink]

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New post 21 Feb 2017, 05:44
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Bunuel wrote:
What is \(2^2*4^4*8^8\)?

A. 2^26
B. 2^34
C. 2^36
D. 64^64
E. 2^384


The answer choices sugggest we might want to rewrite each expression as a power of 2, and then combine all of the expressions.

2^2 = 2^2
4^4 = (2^2)^4 = 2^8
8^8 = (2^3)^8 = 2^24

So, \(2^2 * 4^4 * 8^8\) = \(2^2 * 2^8 * 2^24\)
= \(2^34\)
Answer: B

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Re: What is 2^2*4^4*8^8? [#permalink]

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New post 23 Feb 2017, 10:44
Bunuel wrote:
What is \(2^2*4^4*8^8\)?

A. 2^26
B. 2^34
C. 2^36
D. 64^64
E. 2^384


Let’s express all factors as powers of 2, noting that 4 = 2^2 and 8 = 2^3. We can then simplify the given expression.

2^2 x 4^2 x 8^8

2^2 x (2^2)^4 x (2^3)^8

2^2 x 2^8 x 2^24

2^34

Answer: B
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Re: What is 2^2*4^4*8^8?   [#permalink] 23 Feb 2017, 10:44
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What is 2^2*4^4*8^8?

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