Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 0608:30 AM PDT
-09:30 AM PDT
In Episode 3 of our GMAT Ninja Critical Reasoning series, we tackle Discrepancy, Paradox, and Explain an Oddity questions. You know the feeling: the passage gives you two facts that seem completely contradictory....- May 05
10:00 AM PDT
-11:00 AM PDT
GMAT Inequalities is a high-frequency topic in GMAT Quant, but many students struggle because the concepts behave differently from standard algebra. Understanding the right rules, patterns, and edge cases can significantly improve both speed and accuracy. - May 08
08:00 AM PDT
-08:30 AM PDT
Join the special YouTube live-stream for selecting the winners of GMAT Club MBA Scholarships sponsored by Juno live. Watch who gets these coveted MBA scholarships offered by GMAT Club and Juno.
12 Oct 2020, 12:19
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:48) correct
39%
(01:44)
wrong
based on 31
sessions
History
Date
Time
Result
Not Attempted Yet
What is the measurement of angle p?
(A) 10
(B) 20
(C) 30
(D) 35
(E) 40
(A) 10
(B) 20
(C) 30
(D) 35
(E) 40
Attachments
File comment: YOU CAN CONSIDER THIS DIAGRAM TOO.
ANGLE P.png [ 149 KiB | Viewed 1867 times ]
File comment: Geometry
What is the measurement of angle p.png [ 144.56 KiB | Viewed 1912 times ]
globaldesi
Joined: 28 Jul 2016
Last visit: 23 Feb 2026
Posts: 1,140
Given Kudos: 67
Location: India
Concentration: Finance, Human Resources
Schools: ISB '18 (D)
GPA: 3.97
WE:Project Management (Finance: Investment Banking)
Products:
12 Oct 2020, 22:31
Kudos
Bookmarks
\( \angle\) PAD = 70\({\circ}\) (\( \angle\) BCE + \(\angle\) BCD = 180 so \(\angle\)BCE = 70 and again \(\angle\) BCD +\(\angle\) BAC is supplementary (cyclic angles property) so \(\angle\) BAC = 110 so \(\angle\) PAD = 180 -110 = 70)
\(\angle\) PDA = 80\({\circ}\) (180-110 )
PAD is a triangle so \(\angle\) DPA = 180- (70+80) = 30\({\circ}\)
thus C
\(\angle\) PDA = 80\({\circ}\) (180-110 )
PAD is a triangle so \(\angle\) DPA = 180- (70+80) = 30\({\circ}\)
thus C
13 Oct 2020, 00:51
Kudos
Bookmarks
globaldesi
Thank you for the solution. But did you mean angle BAD instead of BCE?
Whatever I used a different way using the cyclic property.
Angle BCE IS AN EXTERIOR ANGEL WHICH IS EQUAL TO ANGLE BAD = 110
SO ANGLE BCD =70 AND ANLE ABD = 80
SO THE ANGLE P = 30
