what is the area of a right triagle with sides y+2, y, y-2

Question

conocieur · Answer

Got it now:

let's have y+2 and y-2 and is a right triangle:

so the values 8-12-20 would satisfy the constrain, a 8-12-20 is of the right triangle family 3-4-5

so Y = 10 

and the area 48

ipc302 · Answer

since its a right angle triangle the two sides of traingle breath and height will be and x and x-2 and the hypotoneus will be x +2 

 so the area will be (1/2) *x * (x-2)

 

Note :- if u use pythagoras theorem i.e x ^2 + (x - 2) ^2 = (x +2)^2
 
 u will get the value of x as 0 and 8 ... since 0 means that there is no traingle so the value of x will be 8 hence that way the area will be 24.

Avis · Answer

beats me..how did u get the height and base lenghts?

razrulz · Answer

i am not getting it... (x-2)^2 = x^2 +4-4x == x^2+(x-2)^2 =x^2-2x+2 how did u get this as (x+2)^2 ? i dont understand.. pls correct my mistake here...

ipc302 · Answer

I used the phythagoras theroem which says if a,b,c are sides of a right angle traingle with c as hypotoneous then 

 a^2 + b^2 = c^2

 in the above example x and x-2 are the sides and x+2 as hypotoneous 
of a right angle traingle 

so i took x ^2 + (x - 2) ^2 = (x +2)^2 

also remember the rule for right angle traingle 3,4,5 and its similar ratio 6 8 10 all of these are right angle traingle with 5 and 10 hypotoneous , so in this question they just twisted it by putting x-2,x,x+2 instead of 6,8 ,10 .

one more commonly used figure is 5,12,13 

Hope the above helps.

Professor · Answer

i couldnot get your opinion. but the only combination for a right angle triangle that has sides (y-2), y and (y+2) is (6-8-10). so the are area = 1/2(6x8) = 24.

joemama142000 · Answer

oa is 24,

thanks guys

My problem was that i did not know which was the hypotenuse

Professor · Answer

hypoteneous is always the longest side i.e. y+2.

ps_dahiya · Answer

y+2 is hypotenuse and other two are sides.

y ^2 + (y - 2) ^2 = (y +2)^2

Solving this we get y = 0 or y = 8 . So y = 8

Then all three sides are 6,8,10.

So area = 1/2 * 6 * 8 = 24

what is the area of a right triagle with sides y+2, y, y-2

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