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01 Feb 2022, 07:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:55) correct
27%
(02:00)
wrong
based on 37
sessions
History
Date
Time
Result
Not Attempted Yet
What is the area of the circle centered at O and inside of square PQRS?
A. \(\frac{25}{8} \pi\)
B. \(\frac{25}{4} \pi\)
C. \(\frac{25}{2} \pi\)
D. \(25 \pi\)
E. \(50 \pi\)
Attachment:
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yashikaaggarwal
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01 Feb 2022, 08:12
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Just like the diagonal of a square = side*√2
Side of square = diagonal/√2
And the diameter of the circle = side of the square.
Radius = 1/2*5/√2
Radius = 5/2√2
Area of circle = πr^2
=> π(5/2√2)^2
=> π(25/8)
Answer is A
Posted from my mobile device
Side of square = diagonal/√2
And the diameter of the circle = side of the square.
Radius = 1/2*5/√2
Radius = 5/2√2
Area of circle = πr^2
=> π(5/2√2)^2
=> π(25/8)
Answer is A
Posted from my mobile device
03 Feb 2022, 02:47
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Diagonal of the square d = 5
Area of a square with a diagonal = (d^2)/2 = 25/2
Area of an inscribed circle = π/4 * Area of a square = π/4 * 25/2 = 25π/8 (A)
Area of a square with a diagonal = (d^2)/2 = 25/2
Area of an inscribed circle = π/4 * Area of a square = π/4 * 25/2 = 25π/8 (A)
