SajjadAhmad wrote:
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What is the area of the circle with center M shown above?
(1) The length of AC is \(8 \sqrt{2}\)
(2) The length of arc ABC is \(4π\)
IMO D
from 1) length of AC is given, now from this we can calculate the radius -> area
Since AM = AC, it becomes an isosceles triangle
from 2) length of arc is given
from here again we can calculate the radius -> area
theta/360 * 2\(π\) r, can be used
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Quote which i can relate to.
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