|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
18 Jul 2018, 21:26
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:30) correct
32%
(01:39)
wrong
based on 41
sessions
History
Date
Time
Result
Not Attempted Yet
What is the area of the quadrilateral shown above?
A. \(2\sqrt{3}\)
B. \(3\sqrt{3}\)
C. 6
D. \(6\sqrt{3}\)
E. 8
Attachment:
2018-07-19_0825.png [ 31.22 KiB | Viewed 5717 times ]
18 Jul 2018, 21:45
Kudos
Bookmarks
Area of quadrilateral = (a+b/2)×h
Let the vertices be A,B,C,D (From top left in clockwise)
Consider right angle triangle ABE (Drop 2 perpendiculars E,F on CD)
EF=2
ED=CF=1
Apply Pythagoras theorem,
AD^2=ED^2+AE^2
4=1+AE^2
AE=Height of quadrilateral=√3
Area of quadrilateral= ((AB+CD)/2)×H
= ((2+4)/2)×√3
= 3√3
Answer:B
Posted from my mobile device
Let the vertices be A,B,C,D (From top left in clockwise)
Consider right angle triangle ABE (Drop 2 perpendiculars E,F on CD)
EF=2
ED=CF=1
Apply Pythagoras theorem,
AD^2=ED^2+AE^2
4=1+AE^2
AE=Height of quadrilateral=√3
Area of quadrilateral= ((AB+CD)/2)×H
= ((2+4)/2)×√3
= 3√3
Answer:B
Posted from my mobile device
18 Jul 2018, 22:07
Kudos
Bookmarks
Bunuel
the trapezium is isosceles trapezium as it has same angles 'a'. it means that the sides will also be same, also given as 2 ....
look at the attached figure.
drop a perpendicular AB on base..
Now two sides are 1:AB:2.... so it is a 30:60:90 triangle and hence sides are 1:\(\sqrt{3}\):2
Perpendicular = AB = \(\sqrt{3}\)
area of trapezium = \(\frac{1}{2}*\sqrt{3}*(4+2)=3\sqrt{3}\)
B
Attachments
2018-07-19_0825.png [ 38.33 KiB | Viewed 5061 times ]
