Bunuel wrote:

What is the area of the triangle in the figure above?

A. \(2+2\sqrt{3}\)

B. \(4\sqrt{3}\)

C. 8

D. \(8\sqrt{3}\)

E. 12

Attachment:

The attachment **2015-12-27_2141.png** is no longer available

Hi,

the Q may be 700+, since you require to know to play around with Geometrical figures..

the best way is to look how we can draw a 90 degree angle , which will help us to break the figure down to simpler terms[img]

http://gmatclub.com/forum/download/file.php?mode=view&id=28776[/img]..

here we see the third angle C shouold be 45, so we draw a perpendicular from B to AC..

now we have two triangles ABD and BCD..

lets see the first triangle BCD..

angle BCD and CBD are 45 and CDB is 90...

\(Hyp = BC= 2\sqrt{2}\)...

so the sides BD and CD=2..

area of BCD=1/2 * 2*2=2...

lets see the second triangle ABD..

it is 30-60-90 triangle...

and therefore the sides BD:AD:AB are in ratio \(1:\sqrt{3}:2\)..

BD is 2, so AD = \(2\sqrt{3}\)..

so \(area = 1/2 * 2\sqrt{3}*2=2\sqrt{3}\)..

\(total Area=2+ 2\sqrt{3}\)

ans A

Attachments

ANGLES.png [ 24.18 KiB | Viewed 1401 times ]

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1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372

2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html

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