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Can someone elaborate on why AED = BEC please?
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iamdt
Can someone elaborate on why AED = BEC please?


Hello iamdt. As mentioned in my post, triangles lying on the same base and between 2 parallel lines have the same areas.

So Area of ΔADC = Area of ΔBDC

Now since Δ DEC is common to both triangles, the remaining area of the 2 triangles will be equal.

Therefore Area of ΔAED = Area of ΔBEC


Hope this helps


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The area of a triangle is ½×BASE×HEIGHT. Therefore, two triangles with the same base and an equal height will have equal areas. ΔACD and ΔBCD share the same base CD. As to the height:

The height of triangle ADC is AD, while the height of triangle DBC is a line drawn from the vertex B and perpendicular to the extension of side DC: In an obtuse triangle the height may be found outside the triangle, so that it is perpendicular to the extension of the side. However, since angles A and D are right angles, lines AB and CD are parallel, and any height drawn between them will be equal for both ΔACD and ΔBCD. Hence the height of ΔACD is equal to the height of ΔBCD.

Since The two triangles share the same base and have equal heights, the area of ΔACD=The area of ΔBCD.
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