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What is the difference between the average (arithmetic mean) and the m

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New post 17 May 2017, 01:34
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A
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E

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Question Stats:

91% (00:55) correct 9% (01:22) wrong based on 51 sessions

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What is the difference between the average (arithmetic mean) and the median of 40, 41, 42, 43, 44, 45, and 46?

A. 0
B. 1
C. 1.5
D. 2
E. 2.5

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New post 17 May 2017, 02:31
40, 41,42,43,44,45,46

median =43

AM = (40+41+42+43+44+45+46)/7 =43

Difference = 43-43=0
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Re: What is the difference between the average (arithmetic mean) and the m  [#permalink]

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New post 17 May 2017, 02:49
Average (arithmetic mean) of the given series= \(\frac{(40+41+42+43+44+45+46)}{7}\)= 43
Median of the given series is the middle value:
Middle Value is 43. So, median = 43

Difference= 43-43= 0

Answer: A.

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New post 17 May 2017, 04:54
1
If a given set of numbers are in Arithmetic Progression (AP), then
their Arithmetic Mean = their Median.
This is true for every AP series.

So, in that case difference between Arithmetic Mean and Median is 0.

We can observe that the given set of numbers are in AP (With a common difference of 1).
Hence difference between Arithmetic Mean and Median will be 0.
Answer is A
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New post 19 May 2017, 01:52
==> For consecutive integers, the median and the average is equal. Thus, the difference is always 0.

The answer is A.
Answer: A
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New post 07 Aug 2017, 22:33
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Re: What is the difference between the average (arithmetic mean) and the m   [#permalink] 07 Aug 2017, 22:33
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