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# What is the difference between the average (arithmetic mean) and the m

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What is the difference between the average (arithmetic mean) and the m [#permalink]

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17 May 2017, 00:34
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What is the difference between the average (arithmetic mean) and the median of 40, 41, 42, 43, 44, 45, and 46?

A. 0
B. 1
C. 1.5
D. 2
E. 2.5
[Reveal] Spoiler: OA

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Re: What is the difference between the average (arithmetic mean) and the m [#permalink]

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17 May 2017, 01:31
40, 41,42,43,44,45,46

median =43

AM = (40+41+42+43+44+45+46)/7 =43

Difference = 43-43=0
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Re: What is the difference between the average (arithmetic mean) and the m [#permalink]

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17 May 2017, 01:49
Average (arithmetic mean) of the given series= $$\frac{(40+41+42+43+44+45+46)}{7}$$= 43
Median of the given series is the middle value:
Middle Value is 43. So, median = 43

Difference= 43-43= 0

Kudos please if you like my explanation!
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What is the difference between the average (arithmetic mean) and the m [#permalink]

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17 May 2017, 03:54
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KUDOS
If a given set of numbers are in Arithmetic Progression (AP), then
their Arithmetic Mean = their Median.
This is true for every AP series.

So, in that case difference between Arithmetic Mean and Median is 0.

We can observe that the given set of numbers are in AP (With a common difference of 1).
Hence difference between Arithmetic Mean and Median will be 0.
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Re: What is the difference between the average (arithmetic mean) and the m [#permalink]

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19 May 2017, 00:52
==> For consecutive integers, the median and the average is equal. Thus, the difference is always 0.

The answer is A.
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Re: What is the difference between the average (arithmetic mean) and the m [#permalink]

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07 Aug 2017, 21:33
Fun fact -> For any Arithmetic progression => Mean = Median = Average of the first and the last term.

Hence the mean = median => Difference = ZERO.

Hence A.
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Re: What is the difference between the average (arithmetic mean) and the m   [#permalink] 07 Aug 2017, 21:33
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# What is the difference between the average (arithmetic mean) and the m

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