Maybe I just like to work harder than everyone else. Here is how I arrived at B.

Locus = perpendicular bisector.

Find the mid point between A & B. 6 - -2 = 8 and 3 - 1 = 2, so go right 8 and up 2, so midpoint is half that. Go right 4, and up 1. Brings us to {2, 2}. Slope of AB is 1/4 because rise over run 2 up 8 right = \(\frac{2}{8}\) or \(\frac{1}{4}\).

The prependicular line to this will be inverted and the sign flipped. Inverse of 1/4 is 4/1 and negative is -4. To find the x-intercept you have to move left from 2,2 so go up 4, but left, or negative 1. (If you have 4/1, if you move in a positive direction for one of the numbers 4 or 1, the other must move in a negative direction). Up 4 and left 1 brings you to point 1, 6, that's not the x yet, so up 4 and left 1 again brings us to 0 ,10. x-intercept of +10.

Now this perpendicular line is represented by the equation y = -4x + 10. Find the answer that will give you that when solved for y. This is B

y + 4x = 10

y = 10 - 4x or

y = -4x +10

ritula wrote:

What is the equation that represents the locus of points equidistant from the points A (-2, 1) and B (6, 3)?

(A) 4x+y=20

(B) y+4x=10

(C) 4y+x=10

(D) y+2x=20

(E) x+4y=40

I know that its pretty simple question, but sumhow im not getting the right answer. pls help!

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J Allen Morris

**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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