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21 Apr 2016, 00:39
Kudos
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D
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Difficulty:
15%
(low)
Question Stats:
78% (01:01) correct
22%
(01:15)
wrong
based on 287
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What is the greatest value of positive integer x such that 2^x is a factor of 100^80?
A. 40
B. 80
C. 100
D. 160
E. 240
A. 40
B. 80
C. 100
D. 160
E. 240
21 Apr 2016, 02:13
Kudos
Bookmarks
Bunuel
Put in simple words, we need to find the highest power of 2 in 100^80
100 = 2^2*5^2
Therefore 100^80 = (2^2*5^2)^80 = 2^160*5^160
Correct Option: D
09 Oct 2019, 20:14
Kudos
Bookmarks
Bunuel
100^80 = (2^2 * 5^2)^80 = 2^160 * 5^160
Thus, the maximum value of x is 160.
Answer: D
