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What is the largest integer n such that 1/2^n > 0 ?
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10 Feb 2014, 23:45
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The Official Guide For GMAT® Quantitative Review, 2ND EditionWhat is the largest integer n such that \(\frac{1}{2^n}> 0.01\) ? (A) 5 (B) 6 (C) 7 (D) 10 (E) 51 Problem Solving Question: 86 Category: Arithmetic Exponents; Operations with rational numbers Page: 73 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: What is the largest integer n such that 1/2^n > 0 ?
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Re: What is the largest integer n such that 1/2^n > 0 ?
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11 Feb 2014, 00:38
0.01=1/100 So the question is \(2^n<100\) We should know that: 2^5=32 2^6=64 2^7=128 so the ans is 6. B
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Re: What is the largest integer n such that 1/2^n > 0 ?
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11 Feb 2014, 00:45
1/(2^n) > 1/100
Since, 2^6 = 64, 1/64 > 1/100. Answer (B).
It cannot be 7 because 2^7 = 128 and 1/128 < 1/100.



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Re: What is the largest integer n such that 1/2^n > 0 ?
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11 Feb 2014, 13:24
Took me a while but i think it should be 1/2^n > 1/100 so we need to compare really the maximum value of 2^n such that it is less than 100, because if it is more than 100 then 1/2^n becomes less than 1/100
2^5 = 32 2^6 = 64 2^7 = 128
So n cannot be 7 and the largest value it can have while still keeping 1/2^n > 1/100 will be 6 B



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Re: What is the largest integer n such that 1/2^n > 0 ?
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15 Feb 2014, 05:51



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Re: What is the largest integer n such that 1/2^n > 0 ?
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26 Jun 2014, 01:24
\(\frac{1}{2^n} > \frac{1}{100}\) With numerators of both sides same, for LHS > RHS, denominator of LHS should be less than that of RHS \(2^6 = 64\) \(2^7 = 128\) Answer = 6 = B
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Re: What is the largest integer n such that 1/2^n > 0 ?
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10 Jul 2014, 10:40
Bunuel wrote: SOLUTION
What is the largest integer n such that \(\frac{1}{2^n}> 0.01\) ?
(A) 5 (B) 6 (C) 7 (D) 10 (E) 51
[m]\frac{1}{2^n}> 0.01[/m];
\(\frac{1}{2^n}> \frac{1}{100}\);
\(2^n<100\);
\(2^6=64<100\) and \(2^7=128>100\), therefore, 6 is the largest integer such that \(\frac{1}{2^n}> 0.01\).
Answer: B. Hi I could not understand highlighted step.. How 2^1/n >1/100 .....turned in to 2^n<100???? I know i may be missing some basic concept here..Please advice Thanks Komal



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Re: What is the largest integer n such that 1/2^n > 0 ?
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10 Jul 2014, 10:40
Bunuel wrote: SOLUTION
What is the largest integer n such that \(\frac{1}{2^n}> 0.01\) ?
(A) 5 (B) 6 (C) 7 (D) 10 (E) 51
[m]\frac{1}{2^n}> 0.01[/m];
[color=#ff0000]\(\frac{1}{2^n}> \frac{1}{100}\);
\(2^n<100\); [/color] \(2^6=64<100\) and \(2^7=128>100\), therefore, 6 is the largest integer such that \(\frac{1}{2^n}> 0.01\).
Answer: B. Hi I could not understand highlighted step.. How 2^1/n >1/100 .....turned in to 2^n<100???? I know i may be missing some basic concept here..Please advice Thanks Komal



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Re: What is the largest integer n such that 1/2^n > 0 ?
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Re: What is the largest integer n such that 1/2^n > 0 ?
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10 Sep 2014, 12:56
Bunuel wrote: The Official Guide For GMAT® Quantitative Review, 2ND EditionWhat is the largest integer n such that \(\frac{1}{2^n}> 0.01\) ? (A) 5 (B) 6 (C) 7 (D) 10 (E) 51 Problem Solving Question: 86 Category: Arithmetic Exponents; Operations with rational numbers Page: 73 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you! Tip : That is 1 /(2^n) Not 2^(1/n) .



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Re: What is the largest integer n such that 1/2^n > 0 ?
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23 Jun 2017, 13:08
\(\frac{1}{2^n}> 0.01\) \(\frac{1}{2^n}> 1/100\) \(2 ^n < 100\) We need to find largest value of n which satisfies the above value. \(2^6 = 64\) is the maximum value of n that satisfies above equation. Hence, Answer is B = 6
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Re: What is the largest integer n such that 1/2^n > 0 ?
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21 Feb 2018, 05:50
Why we shift the sign
2^n<100
Not 2^n>100



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Re: What is the largest integer n such that 1/2^n > 0 ?
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22 Feb 2018, 16:49
Bunuel wrote: The Official Guide For GMAT® Quantitative Review, 2ND EditionWhat is the largest integer n such that \(\frac{1}{2^n}> 0.01\) ? (A) 5 (B) 6 (C) 7 (D) 10 (E) 51 Converting 0.01 to a fraction we have: 1/(2^n) > 1/100 We can reciprocate the inequality above (remember to switch the inequality sign) to have: 2^n < 100 The largest integer such that 2^n < 100 is 6 since 2^6 = 64 and 2^7 = 128. So n must be 6. Answer: B
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Re: What is the largest integer n such that 1/2^n > 0 ?
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28 Feb 2018, 21:49
Hi All, Since the answers to this question are numbers, we can use them to our advantage and TEST THE ANSWERS. We're told that N has to be an INTEGER and we want to make N as LARGE as possible so that 1/(2^N) > .01 Since this inequality uses a fraction on one side and a decimal on the other, I'm going to convert the decimal to a fraction. This gives us.... 1/(2^N) > 1/100 We want to make N as LARGE as possible while still maintaining the inequality. This means that we have to make 2^N as BIG as possible BUT it still has to be less than 100. One of the 5 answer choices MUST be correct, so let's TEST THE ANSWERS.... If N = 5, 2^5 = 32 1/32 > 1/100 If N = 6, 2^6 = 64 1/64 > 1/100 If N = 7, 2^7 = 128 1/128 is NOT > 1/100 So the BIGGEST that N could be is 6. Final Answer: GMAT assassins aren't born, they're made, Rich
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What is the largest integer n such that 1/2^n > 0 ?
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28 Feb 2018, 22:37
Plugged in the numbers given in options to find the solution 1/\(2^{n}\) > 1/100 We can substitute the numbers in answer choices and find the solution. Lets take the highest number 7 since question ask for highest number \(1/2^{7}\)= 1/128 is lesser than 1/100 , so 7 is not our answer. \(1/2^{6}\) = 1/64 which is higher than 1/100 and since 6 is also the highest possible number, our answer is 6. Ans: B
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Re: What is the largest integer n such that 1/2^n > 0 ?
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23 Mar 2018, 04:29
Bunuel wrote: GGMAT760 wrote: Bunuel wrote: SOLUTION
What is the largest integer n such that \(\frac{1}{2^n}> 0.01\) ?
(A) 5 (B) 6 (C) 7 (D) 10 (E) 51
[m]\frac{1}{2^n}> 0.01[/m];
\(\frac{1}{2^n}> \frac{1}{100}\);
\(2^n<100\);
\(2^6=64<100\) and \(2^7=128>100\), therefore, 6 is the largest integer such that \(\frac{1}{2^n}> 0.01\).
Answer: B. Hi I could not understand highlighted step.. How 2^1/n >1/100 .....turned in to 2^n<100???? I know i may be missing some basic concept here..Please advice Thanks Komal Crossmultiply \(\frac{1}{2^n}> \frac{1}{100}\) to get \(2^n<100\). Why are we changing inequility sign direction after we cross multiply ? there are no negatives sign to cause the inequlity sign change we only change sign when we divide or multiply by negative value, right ?



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What is the largest integer n such that 1/2^n > 0 ?
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23 Mar 2018, 04:39
dave13 wrote: Why are we changing inequility sign direction after we cross multiply ? there are no negatives sign to cause the inequlity sign change we only change sign when we divide or multiply by negative value, right ? Hey dave13 , We are not changing the sign of the inequality. If I am saying 2 < 3 , can't I also say 3 > 2 ? This is exactly the same Bunuel did. \(\frac{1}{2^n}> \frac{1}{100}\) is equal to \(100> 2^n\), which is equal to \(2^n<100\) Does that make sense?
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What is the largest integer n such that 1/2^n > 0 ?
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24 Jun 2018, 05:00
gmatbusters chetan2u niks18 VeritasPrepKarishma pushpitkcQuote: \(\frac{1}{2^n}> \frac{1}{100}\);
\(2^n<100\); To recall above steps, i.e. flip inequality while reversing the fraction, do I need to take simple examples as 2 < 3 hence 1/2 > 1/3 or there is a better approach? Why does sign of 'n' does not matter? Bunuel can you please add relevant discussion in this post?
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Re: What is the largest integer n such that 1/2^n > 0 ?
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