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# What is the largest integer n such that 2^n is a factor of 2

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Joined: 10 Jul 2013
Posts: 315
What is the largest integer n such that 2^n is a factor of 2  [#permalink]

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Updated on: 20 Aug 2013, 12:25
2
00:00

Difficulty:

5% (low)

Question Stats:

81% (00:42) correct 19% (01:06) wrong based on 170 sessions

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What is the largest integer n such that 2^n is a factor of 20^8 ?

(A) 1
(B) 2
(C) 4
(D) 8
(E) 16

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Asif vai.....

Originally posted by Asifpirlo on 20 Aug 2013, 12:24.
Last edited by Bunuel on 20 Aug 2013, 12:25, edited 1 time in total.
Edited the question.
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Concentration: General Management, Operations
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Re: 1. What is the largest integer n such that 2^n is a factor  [#permalink]

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20 Aug 2013, 12:27
1
Asifpirlo wrote:
1. What is the largest integer n such that 2^n is a factor of 20^8 ?

(A) 1 (B) 2 (C) 4 (D) 8 (E) 16
.

$$20^8 = (2*2*5)^8 = 2^{16}*5^8$$
CLEARLY maximum possible value of $$n = 16$$

hence E
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Re: What is the largest integer n such that 2^n is a factor of 2  [#permalink]

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20 Aug 2013, 12:27
2
Asifpirlo wrote:
What is the largest integer n such that 2^n is a factor of 20^8 ?

(A) 1
(B) 2
(C) 4
(D) 8
(E) 16

$$20^8=(2^2*5)^8=2^{16}5^8$$. Therefore the largest integer n such that 2^n is a factor of $$2^{16}5^8$$ is 16.

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What is the largest integer n such that 2^n is a factor of 20^8?  [#permalink]

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17 Oct 2017, 12:21
What is the largest integer n such that 2^n is a factor of 20^8?

(A) 1
(B) 2
(C) 4
(D) 8
(E) 16

$$20^8=(4*5)^8=2^{16}*5^8$$

so $$n=16$$

Option E
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What is the largest integer n such that 2^n is a factor of 2  [#permalink]

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17 Oct 2017, 21:04
Similar question: https://gmatclub.com/forum/what-is-grea ... 22444.html
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What is the largest integer n such that 2^n is a factor of 2 &nbs [#permalink] 17 Oct 2017, 21:04
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